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Alex17521 [72]
3 years ago
14

What transformation transforms (a, b) (a, -b)

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

We have

(a, b ) → (a, - b ) ← reflection in the x- axis

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The table below shows the number of customers that come eat lunch at a local deli each week.
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The table of the number of customers illustrates two different patterns

Deli should expect 90 customers to serve during week 8

<h3>How to determine the number of customers</h3>

From the table, the even number of week increases by 10, while the odd number of weeks reduces by 5.

At week 6, the number of customers is 80.

So, the number of customers at week 8 is:

Week 8 = Week 6 + 10

This gives

Week 8 = 80 + 10

Week 8 = 90

Hence, deli should expect 90 customers to serve during week 8

Read more about sequence and patterns at:

brainly.com/question/15590116

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The sum of x and ten is twenty( write the equation
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Answer:

2x10=20 X=2

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Y=-2x+2 Y=-2x-2 state the solution
Arisa [49]

Answer:

Step-by-step explanation:

Y=-2x+2.....(1)

Y=-2x-2.....(2)

Subtracting (1) from (2)

Y - Y = -2x - (-2x) -2 - 2

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A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula
kvasek [131]

Answer:

The sample proportion of printers used in small business is:

\hat{p}=\frac{25}{70}=0.3571

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

Where:

z_{\frac{0.05}{2}}=1.96 is the critical value at 0.05 significance level

\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }

         0.3571 \pm 0.1122

         \left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)

         \left(0.245,0.469 \right)

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)



7 0
3 years ago
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