Answer:
2
Step-by-step explanation:
loge(x) is ln(x)
f(x) × ln(x)
Differentiate using product law
[ln(x) × f'(x)] + [(1/x) × f(x)]
x = 1
[ln(1) × f'(1)] + [(1/1) × f(1)]
(0 × 4) + (1 × 2)
0 + 2
2
Answer: B: 24q+48r
Step-by-step explanation: 6(4q+8r)
=(6)(4q+8r)
=(6)(4q)+(6)(8r)
=24q+48r

now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38
so set x = 1.38 and see what "y" is
Gemma would need to pay $3,436.16 to be able to purchase the car she wants.