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A gas turbine has a thermal efficiency of 20% and develops a power output of 8 MW. Determine the fuel consumption rate if heatin

AlexFokin [52]

Answer:

0.8 kilograms of fuel are consumed each second.

Explanation:

As turbines are steady-state devices, the thermal efficiency of a turbine is equal to the percentage of the ratio of the output power to fluid power, that is:

$\eta_{th} = \frac{\dot W}{\dot E} \times 100\,\%$

The fluid power is:

$\dot E = \frac{\dot W}{\eta} \times 100\,\%$

$\dot E = \frac{8\,MW}{20\,\%}\times 100\,\%$

$\dot E = 40\,MW$

Which means that gas turbine consumes 40 megajoules of fluid energy each second, which is heated and pressurized with help of the fuel, whose amount of consumption per second is:

$50\,\frac{MJ}{kg} = \frac{40\,MJ}{m_{fuel}}$

$m_{fuel} = 0.8\,kg$

0.8 kilograms of fuel are consumed each second.

3 0

3 years ago

The function below takes a two parameters: a list called a_list and a value called a_value. Complete the function to first check

Alik [6]

Explanation:

def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value

if a_value in list://if statement to

//check if it's in the list or not

print("")//print statement to do

//nothing

else://else statement for if the

//a_value is in a_list

a_list.append(a_value)//this adds

//the value to the list

5 0

3 years ago

In details and step-by-step, show how you apply the Bubble Sort algorithm on the following list of values. Your answer should sh

astraxan [27]

( 12 17 18 19 25 )

Explanation:

First Pass:

( 19 18 25 17 12 ) –> ( 18 19 25 17 12 ), Here, algorithm compares the first two elements, and swaps since 19 > 18.

( 18 19 25 17 12 ) –> ( 18 19 25 17 12 ), Now, since these elements are already in order (25 > 19), algorithm does not swap them.

( 18 19 25 17 12 ) –> ( 18 19 17 25 12 ), Swap since 25 > 17

( 18 19 17 25 12 ) –> ( 18 19 17 12 25 ), Swap since 25 > 12

Second Pass:

( 18 19 17 12 25 ) –> ( 18 19 17 12 25 )

( 18 19 17 12 25 ) –> ( 18 17 19 12 25 ), Swap since 19 > 17

( 18 17 19 12 25 ) –> ( 18 17 12 19 25 ), Swap since 19 > 12

( 18 17 12 19 25 ) –> ( 18 17 12 19 25 )

Third Pass:

( 18 17 12 19 25 ) –> ( 17 18 12 19 25 ), Swap since 18 > 17

( 17 18 12 19 25 ) –> ( 17 12 18 19 25 ), Swap since 18 > 12

( 17 12 18 19 25 ) –> ( 17 12 18 19 25 )

Fourth Pass:

( 17 12 18 19 25 ) –> ( 12 17 18 19 25 ), Swap since 17 > 12

( 12 17 18 19 25 ) –> ( 12 17 18 19 25 ), Swap since 18 > 12

( 12 17 18 19 25 ) –> ( 12 17 18 19 25 )

Now, the array is already sorted, but our algorithm does not know if it is completed. The algorithm needs one whole pass without any swap to know it is sorted.

Fifth Pass:

( 12 17 18 19 25 ) –> ( 12 17 18 19 25 )

6 0

3 years ago

Write a program that randomly chooses between three different colors for displaying text on the screen. Use a loop to display tw

11Alexandr11 [23.1K]

Answer:

INCLUDE Irvine32.inc

.data

msgIntro byte "This is Your Name's fourth assembly extra credit program. Will randomly",0dh,0ah

byte "choose between three different colors for displaying twenty lines of text,",0dh,0ah

byte "each with a randomly chosen color. The color probabilities are as follows:",0dh,0ah

byte "White=30%,Blue=10%,Green=60%.",0dh,0ah,0

msgOutput byte "Text printed with one of 3 randomly chosen colors",0

.code

main PROC

;

//Intro Message

mov edx,OFFSET msgIntro ;intro message into edx

call WriteString ;display msgIntro

call Crlf ;endl

call WaitMsg ;pause message

call Clrscr ;clear screen

call Randomize ;seed the random number generator

mov edx, OFFSET msgOutput;line of text

mov ecx, 20 ;counter (lines of text)

L1:;//(Loop - Display Text 20 Times)

call setRanColor ;calls random color procedure

call SetTextColor ;calls the SetTextColor from library

call WriteString ;display line of text

call Crlf ;endl

loop L1

exit

main ENDP

;--

setRanColor PROC

;

; Selects a color with the following probabilities:

; White = 30%, Blue = 10%, Green = 60%.

; Receives: nothing

; Returns: EAX = color chosen

;--

mov eax, 10 ;range of random numbers (0-9)

call RandomRange ;EAX = Random Number

.IF eax >= 4 ;if number is 4-9 (60%)

mov eax, green ;set text green

.ELSEIF eax == 3 ;if number is 3 (10%)

mov eax, blue ;set text blue

.ELSE ;number is 0-2 (30%)

mov eax, white ;set text white

.ENDIF ;end statement

ret

setRanColor ENDP

6 0

3 years ago

Two concentric helical compression springs made of steel and having the same length when loaded and when unloaded are used to su

Andrews [41]

Answer:

see explaination for all the answers and full working.

Explanation:

deflection=8P*DN/Gd^4

G(for steel)=70Gpa=70*10^9N/m^2=70KN/mm^2

for outer spring,

deflection=8*3*50^3*5/(70*9^4)=32.66mm

for inner spring

deflection=8*3*30^3*10/(70*5^4)=148.11mm

max stress=k*8*P*C/(3.14*d^2)

for outer spring

c=50/9=5.55

k=(4c-1/4c-4)+.615/c=1.2768

max stress=1.2768*8*3*5.55/(3.14*9^2=.66KN.mm^2

for inner spring

c=6

k=1.2525

max stress=2.29KN/mm^2

6 0

4 years ago

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