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4 years ago

How many liters are equivalent to 645 mililiters

Chemistry

2 answers:

Vinvika [58]4 years ago

8 0

0.645. just divide that by 1000

abruzzese [7]4 years ago

6 0

Answer:

0.645 liters

Explanation:

THE QUESTION IS equivalent 0.645 Liters

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Lol nevermind i figured it out

Scorpion4ik [409]

Hehehehe hi,
If someone else answers please please pleaseeeee mark me as brainliest. Thank youuu

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3 years ago

at 100c the vapour pressure of a solution of 6.5g of solute in 100g of water is 732mm if kb is 0.52 k/m the boiling point of sol

sergey [27]

Answer:101.105⁰c

Explanation:

8 0

3 years ago

Write an equation for the hydrogenation of glyceryl trilinolenate, a fat formed from glycerol and three linolenic acid molecules

Tomtit [17]

Balanced chemical equation for the hydrogenation of glyceryl trilinolenate:

C₅₇H₉₂O₆ + 9H₂ → C₅₇H₁₁₀O₆.

Linolenic acid (octadecatrienoic acids ) is a type of fatty acid. It has 18 carbon atoms chain and three double bonds. So trilinolenate has nine double bonds.

Trilinolenate is the form of triglyceride esters of linolenic acid.

Hydrogenation is addition of hydrogen atoms at both sides of a double bond.

5 0

4 years ago

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

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4 years ago

The combining of two atomic nuclei to produce one larger nucleus is called

Naddika [18.5K]

C.
Nuclear fission involves the high energy collision of two atomic nuclei to produce one larger nucleus; this process powers stars.

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4 years ago