Answer:
thomson's experiments with cathode ray tubes that showed that all atoms contain tiny negatively charged subatomic particles or electrons.
Answer:
Period 4
Explanation:
Given the electronic configuration of the element;
= Is² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p¹
The period of the element is determined by the highest coefficient in the electronic configuration.
For this given configuration (Is² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p¹), "4" is the highest coefficient and the element will certainly belong to period 4 in the periodic table.
To test if the prediction is correct:
Total number of electrons in the given element = 2+2+6+2+6+10+2+1 = 31
The element with atomic number of 31 = Gallium (Ga). (This element belong to period 4).
Answer:
0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.
Explanation:
Step 1: Data given
ΔT = i*Kb*m
⇒ΔT = the boiling point elevation = Shows how much the boiling point increases
⇒i = the van't Hoff factor: Says in how many particles the compound will dissociate
⇒ Since all are aqueous solutions Kb for all solutions is the same (0.512 °C/m)
⇒m = the molality
Step 2:
0.20 m glucose
ΔT = i*Kb*m
⇒ΔT = the boiling point elevation = TO BE DETERMINED
⇒i = the van't Hoff factor for glucose = 1
⇒ Kb = 0.512 °C/m
⇒m = 0.20 m
ΔT = 1*0.512 * 0.20
<u>ΔT = 0.1024 °C</u>
0.30 m BaCl2
ΔT = i*Kb*m
⇒ΔT = the boiling point elevation = TO BE DETERMINED
⇒i = the van't Hoff factor for BaCl2 = Ba^2+ + 2Cl- : i = 3
⇒ Kb = 0.512 °C/m
⇒m = 0.30 m
ΔT = 3*0.512 * 0.30
<u>ΔT = 0.4608 °C</u>
0.40 m NaCl
ΔT = i*Kb*m
⇒ΔT = the boiling point elevation = TO BE DETERMINED
⇒i = the van't Hoff factor for NaCl = Na+ + Cl- : i = 2
⇒ Kb = 0.512 °C/m
⇒m = 0.40 m
ΔT = 2*0.512 * 0.40
<u>ΔT = 0.4096 °C</u>
0.50 m Na2SO4.
ΔT = i*Kb*m
⇒ΔT = the boiling point elevation = TO BE DETERMINED
⇒i = the van't Hoff factor for Na2SO4 = 2Na+ + SO4^2- : i =3
⇒ Kb = 0.512 °C/m
⇒m = 0.50 m
ΔT = 3*0.512 * 0.50
<u>ΔT = 0.768 °C</u>
0.20 m glucose < 0.40 m NaCl < 0.30 m BaCl2 < 0.50 m Na2SO4.
Answer: wipe it with a kimwipe
Explanation:
The reason why 1-hydroxy-2-methyl-5-isopropylbenzene is not the correct systematic name for carvacrol is because the substituents are not listed alphabetically.
IUPAC nomenclature provides the correct and acceptable system of naming organic compounds which are internationally acceptable among scientists.
According to the rules of IUPAC nomenclature, compounds are named in alphabetical order. The names of the locants are ordered in such a way that they have the lowest number. Following IUPAC nomenclature, the correct name of the compound ought to be, 1-hydroxy-5-isopropyl-2-methylbenzene.
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