Answer:
352
Explanation:
.75 times 472 because .25 is sugar so .75 is watet
The final temperature of the water is determined as 50.55 ⁰C.
<h3>
Final temperature of the water</h3>
The final temperature of the water is determined from the following calculations;
Q = mcΔθ
Δθ = Q/mc
where;
- Q is the amount of energy = 81 kcal = 338904 J
- c is specific heat capacity of water = 4,200 J/kgC
Δθ = 338904 /(3.5 x 4200)
Δθ = 23.05 °C
Final temperature = T₁ + Δθ
Final temperature = 27.5°C + 23.05 °C = 50.55 ⁰C.
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Answer,
Add water to dissolve the salt solution.Shake the solution,oil and water are immiscible liquids therefore oil will not dissolve.Put the solution in a separating funnel and leave the solution undisturbed for a few minutes.Water is denser than oil there oil will come to the top.Power the lower layer of water in to a beaker.Boil the water until water turns into vapour leaving the salt behind.
Answer:
The final temperature is equal to 240 K or -33.15°C
Explanation:
Given that,
Initial temperature of the gas, T₁ = 47°C = 320 K
Initial pressure, P₁ = 140 kpa
Final pressure, P₂ = 105 kpa
We need to find the final temperature if the volume remains constant. The relation between temperature and pressure is given by :
or
So, the final temperature is equal to 240 K or -33.15°C.
<span>The pH is given by the Henderson - Hasselbalch equation:
pH = pKa + log([A-]/[HA])
pH = -log(</span><span>1.3 x 10^-5) + log(0.50/0.40)
pH = 4.98
The answer to this question is 4.98.
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