All categories

3 years ago

What does the number 4 represent in 4nh3

Chemistry

1 answer:

inn [45]3 years ago

6 0

The molecules

the means there is 4 compounds of nh3

You might be interested in

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det

murzikaleks [220]

Answer:

0.11 mol

Explanation:

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of oxygen in a sample of acetic acid. How many moles of hydrogen are in the sample?

Step 1: Given data

Formula of acetic acid: CH₃CO₂H

Moles of oxygen in the sample of acetic acid: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula of acetic acid, the molar ratio of H to O is 4:2.

Step 3: Calculate the moles of atoms of hydrogen

We will use the theoretical molar ratio for acetic acid.

0.054 mol O × (4 mol H/2 mol O) = 0.11 mol H

3 0

3 years ago

Is this correct please help?

iren [92.7K]

Answer:

$\boxed {\tt Number \ and \ unit}$

Explanation:

The two requirements for a measurement are a number and a unit.

For example, here is a measurement:

38.6 cm

The number is 38.6 and the unit is cm, or centimeters.

Therefore, both number and unit are correct.

7 0

3 years ago

covalent bond would be formed in which pair of elements? Carbon and oxygen, any two noble gasses, sodium and chlorine , between

SOVA2 [1]

Answer:

Carbon and Oxygen, Argon and Helium.

Explanation:

noble gases have full outer shells of electrons, and so cannot share other atoms' electrons to form bonds. sodium and chlorine form an ionic bond.

4 0

3 years ago

What's the answer to equation Ba+Br2=

Andrej [43]

Answer:

BaBr2, Barium Bromide

Explanation:

7 0

4 years ago

The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate

Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

$a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8$ cm

for a BCC structure, the atomic radius is equal to

$r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3} }{4}=2.3103x10^{-8}cm$

7 0

3 years ago