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lilavasa [31]
3 years ago
15

While spending the weekend in your cabin, you burn wood in your pot-bellied stove to heat a kettle of water for tea. Answer the

following questions for 2 points each:
1. What type of energy does the wood have in this situation. Explain your answer.

2. What type of energy is this transformed into as the wood it burned in the stove. Explain your answer.

3. What type of heat transfer is being used to warm the kettle of water? Why does the water eventually boil?
Chemistry
2 answers:
poizon [28]3 years ago
7 0

Answer:

1. The wood has chemical energy.

2. This chemical energy is transformed into thermal (heat) energy as it burns.

3. When the fire burns, it heats of the kettle of water through radiation of heat.

Explanation:

1. It has chemical energy because when burned, it undergoes a chemical reaction to transform into heat energy, the byproduct of chemical reactions.

2. The chemical energy in the wood is transformed into heat energy because it is a byproduct of chemical reactions.

3. The water eventually boils as enough chemical energy is transformed into heat energy, which heats up the kettle of water and eventually boils it.

cluponka [151]3 years ago
6 0
1. The wood has chemical energy because it is burning.
2. It is transforming into thermal energy as the fire emits heat.
3.The heat transfer is radiation because the fire is radiating heat. It will gain heat and reach 100 degrees celsius which is the boiling point.
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Brass is a substitutional alloy consisting of a solution of copper and zinc. A particular sample of red brass consisting of 79.0
Bas_tet [7]

<u>Answer:</u> The molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

<u>Explanation:</u>

Solute is the substance which is present in smaller proportion in a mixture and solvent is the substance which is present in larger proportion in a mixture.

We are given:

(m/m) % of Cu = 79 %

This means that 79 g of copper is present in 100 grams of alloy.

(m/m) % of Zn = 21 %

This means that 21 g of zinc is present in 100 grams of alloy.

As, zinc is present in smaller proportion. So, it is solute and copper is the solvent.

  • <u>Calculating molality of zinc:</u>

To calculate molality of the zinc, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

m_{solute} = Given mass of solute (Zinc ) = 21 g

M_{solute} = Molar mass of solute (Zinc) = 65.3 g/mol

W_{solvent} = Mass of solvent (copper) = 79 g

Putting values in above equation, we get:

\text{Molality of Zinc}=\frac{21\times 1000}{65.3\times 79}\\\\\text{Molality of zinc}=4.07m

  • <u>Calculating molarity of zinc:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 8740kg/m^3=\frac{8740kg\frac{1000g}{1kg}}{1m^3\times \frac{10^6cm^3}{1m^3}}=\frac{8740g}{1000cm^3}=8.740g/cm^3

(Conversion factors used are:  1 kg = 1000 g &  1m^3=10^6cm^3  )

Mass of solution = 100 g

Putting values in above equation, we get:

8.740g/cm^3=\frac{100.0g}{\text{Volume of zinc}}\\\\\text{Volume of zinc}=11.44cm^3

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molar mass of zinc = 65.3 g/mol

Volume of solution = 11.44cm^3=11.44mL     (Conversion factor:  1cm^3=1mL  )

Mass of zinc = 21.0 g

Putting values in above equation, we get:

\text{Molarity of zinc}=\frac{21\times 1000}{65.3\times 11.44}=28.11M

Hence, the molality and molarity of zinc in the solution is 4.07 m and 28.11 M respectively.

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Answer:

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Explanation:

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Answer:

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yawa3891 [41]

Answer: The chemical formula for the formula given in the image is C_4H_9O_2.

Explanation: There are many ways in which a model can be represented:

  1. Molecular Formula
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This molecule is represented by the Expanded Structural Formula and by seeing in the image we can count the number of each element present.

Number of Carbon atoms present = 4

Number of Hydrogen atom present = 9

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Correct representation for this will be C_4H_9O_2.

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