Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: $H_2O(l)\rightarrow H_2(g)+O_2(g)$

Balanced Equation: $2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: $HgO(s)\rightarrow Hg+O_2$

Balanced Equation: $2HgO(s)\rightarrow 2Hg+O_2$

For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Balanced Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

Balanced Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

3 0

3 years ago

Question 5 (5 points)

Dima020 [189]

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

6 0

2 years ago

Read 2 more answers

what volume of co2 is produced at stp when 270g of glucose are consumed in the following reaction? c6h12o6 + 6o2(g) -> 6co2 (

lana [24]

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

4 0

3 years ago

You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30

dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula: $\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n$