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gtnhenbr [62]
3 years ago
6

Name 3 ways ecologist can estimte the size of population

Chemistry
1 answer:
sergiy2304 [10]3 years ago
8 0
1. Count them
2. Trap, Mark, and Release
3. Sample Count

I hope this helps your score!!
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Why the is ratio of magnesium ions to chloride ions in MgCl2 is 1:2?
Monica [59]
You should read up on Proust's law, better known as the Law of Definite Proportions. This is a chemical law that defines your question more generally, on why the ratio of elements and ions are always fixed.

Basically, this compound Magnesium(II) Chloride is MgCl2 because it has the same number of protons, neutrons, and electrons all the way. This defines the properties of the compound or atom. 
5 0
3 years ago
How many grams of CO2 are in 6 mol of the compound. Need answer and units.
Alex Ar [27]

Answer:

75 g  

Step-by-step explanation:

<em>Step 1</em>. Calculate the molar mass of CO₂

 C                      = 12.01

2O = 2 × 16.00 = <u>32.00 </u>

               Total = 44.01 g/mol

<em>Step 2</em>. Calculate the mass of CO₂

Mass of CO₂ = 6 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

Mass of CO₂ = 75 g CO₂

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3 years ago
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why is H2SO4 considered as strong acid? What colour does it give with phenolphthalein and methyl orange?​
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Ethanol is a possible fuel. Use average bond energies to calculate ΔHrxn for the combustion of ethanol. CH3CH2OH(g) + 3 O2(g) →
Maksim231197 [3]

Explanation:

The reaction is as follows.

       CH_{3}CH_{2}OH(g) + 3O_{2}(g) \rightarrow 2CO_{2} + 3H_{2}O(g)

Standard values of bond energies are as follows.

C-C = 347 kJ/mol

C-H = 414 kJ/mol

C-O = 360 kJ/mol

O-H = 464 kJ/mol

O=O = 498 kJ/mol

C=O = 799 kJ/mol

Hence, calculate the change in enthalpy of the reaction as follows.

 \Delta H_{rxn} = \sum \text{bond energy of reactants} - \sum \text{bond energy of products}

= [5(C-H) + 1(C-C) + 1(C-O) + 1(O-H) + 3(O=O)] - [4(C=O) + 6(O-H)]

 = [5 \times 414 + 1 \times 347 + 1 \times 360 + 1 \times 464 + 3 \times 498] kJ - [4 \times 799 + 6 \times 464]kJ

       = (4735 - 5980) kJ

       = -1245 kJ

Thus, we can conclude that the enthalpy of given reaction is -1245 kJ.

3 0
3 years ago
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