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3 years ago

Describe how you would use a calorimeter to determine the specific heat capacity of a metal

Chemistry

2 answers:

Ymorist [56]3 years ago

4 0

Answer: (see explanation part)

Explanation:

A piece of solid material of specific heat c unknown is weighed with a balance, m resulting in its mass. The piece is put in almost boiling water at temperature T.

M grams of water are put on the calorimeter, it is stirred and after a short time, its temperature T0 is measured.

The solid part is quickly deposited in the calorimeter. It is stirred, and after a certain time the equilibrium temperature Te is reached.

The data is recorded and c is cleared of the formula that's attached (please take a look).

vovikov84 [41]3 years ago

3 0

<span>My only guess is obtain a metal and heat it in a boiling water bath (of known temperature) this will be your initial temperature. Now obtain a calorimeter cup with water of known temperature as well. Place the metal into the calorimeter cup and record the temperature after 5 minutes. You now have delta T, mass of the metal, and Q. Solve for C.

Hope this helps xox :)</span>

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You bought a new car and estimated that your monthly payment would be $312. However, your actual payment amount was $325. How mu

Romashka-Z-Leto [24]

Answer:

The error would be $13.

Explanation:

Given data:

Actual payment = $325

estimated payment = $312

Error = ?

Solution:

Error = Estimated payment - Actual payment

Error = $312 - $325

Error = -$13

we can discard the negative sign and consider the absolute value. The error would be $13.

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4 years ago

You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid

Art [367]

Answer:

$V_1=2.49mL$

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

$n_{HI}=n_{HI}$

One could apply the following equality in terms of molarity:

$V_1M_1=V_2M_2$

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

$V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL$

Best regards.

5 0

3 years ago

Can someone please help me?

irina [24]

Answer:
your answer is hawks

3 0

3 years ago

Read 2 more answers

What happens to the electron cloud at very high atomic numbers, when the innermost electrons would, using a non-relativistic mod

marin [14]

Answer:

tough question

Explanation:

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2 years ago

When 5ml of HCl was added

777dan777 [17]

Answer:

A. There was still 140 ml of volume available for the reaction

Explanation:

According to Avogadro's law, we have that equal volumes of all gases contains equal number of molecules

According to the ideal gas law, we have;

The pressure exerted by a gas, P = n·R·T/V

Where;

n = The number of moles

T = The temperature of the gas

R = The universal gas constant

V = The volume of the gas

Therefore, given that the volumes and number of moles of the removed air and added HCl are the same, the pressure and therefore, the volume available for the reaction will remain the same

There will still be the same volume available for the reaction.

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3 years ago