Answer:
The correct option is A.
Explanation:
Following the equation of continuum, AV remains constant.
Case a
(3A)(V0) = AV1 + AV1 + AV1
3AV0 = 3AV1
V1 = V0
Case b
(A)(V0) = (A/3)V2 + (A/3)V2 + (A/3)V2 + (A/3)V2
AV0 = 4V2/3
V2 = 3/4V0
Case c
(A/2)(V0) = AV3 + AV3 + AV3
AV0/2 = 3AV3
V3 = V0/6
Case d
(3A)(V0) = 2AV4 + 2AV4
3AV0 = 4AV4
V4 = 3V0/4
Comparing all the flow speeds, V1 is the largest.
Thus, the correct option is A.
Answer:
<h2>99 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 9 × 11
We have the final answer as
<h3>99 J</h3>
Hope this helps you
<span>An event that breaks objects into smaller objects or pieces is called destructive force
</span><span>Tornadoes, Hurricanes, Earthquakes, Volcanoes, Tsunamis and more are some of examples
</span><span>Forces that wear down, destroy is right answer</span>
2.57 joule energy lose in the bounce
.
<u>Explanation</u>:
when ball is the height of 1.37 m from the ground it has some gravitational potential energy with respect to hits the ground
Formula for gravitational potential energy given by
Potential Energy = mgh
Where
,
m = mass
g = acceleration due to gravity
h = height
Potential energy when ball hits the ground
m= 0.375 kg
h = 1.37 m
g = 9.8 m/s²
Potential Energy = 5.03 joule
Potential energy when ball bounces up again
h= 0.67 m
Potential Energy = 2.46 joule
Energy loss = 5.03 - 2.46 = 2.57 joule
2.57 joule energy lose in the bounce
Answer:
T = 4.42 10⁴ N
Explanation:
this is a problem of standing waves, let's start with the open tube, to calculate the wavelength
λ = 4L / n n = 1, 3, 5, ... (2n-1)
How the third resonance is excited
m = 3
L = 192 cm = 1.92 m
λ = 4 1.92 / 3
λ = 2.56 m
As in the resonant processes, the frequency is maintained until you look for the frequency in this tube, with the speed ratio
v = λ f
f = v / λ
f = 343 / 2.56
f = 133.98 Hz
Now he works with the rope, which oscillates in its second mode m = 2 and has a length of L = 37 cm = 0.37 m
The expression for standing waves on a string is
λ = 2L / n
λ = 2 0.37 / 2
λ = 0.37 m
The speed of the wave is
v = λ f
As we have some resonance processes between the string and the tube the frequency is the same
v = 0.37 133.98
v = 49.57 m / s
Let's use the relationship of the speed of the wave with the properties of the string
v = √ T /μ
T = v² μ
T = 49.57² 18
T = 4.42 10⁴ N
