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1 year ago

Which statement is true regarding a distance vs. time graph? (1 point)

2 answers:

Nadusha1986 [10]1 year ago

6 0

The statement that is true regarding a distance vs. time graph is option A: The graph should show distance on the vertical axis.

<h3>Where is the plot of distance?</h3>

How far an object has come in a certain amount of time is displayed on a distance-time graph. Time is represented on the X-axis and Distance is plotted on the Y-axis (left) (bottom).

On a distance-time graph, an object's motion is indicated by a sloping line. The slope or gradient of the line in a distance-time graph is equal to the object's speed. The object is travelling more quickly the steeper the line is (and the bigger the gradient).

Note that the distance-time graph shows the relationship between distance and time by plotting distance on the y-axis and time on the x-axis.

Learn more about distance vs. time graph from

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Lena [83]1 year ago

4 0

Answer:

(Question) Which quantity is scalar?

(Answer) Energy

(Question) Which option describes a vector quantity?

(Answer) It has magnitude, units, and direction.

(Question) A sailboat ends up 7 miles to the west of a pier. Which statement is true about this situation?

(Answer) It describes displacement, which is a vector quantity.

(Question) Which statement is true regarding a distance vs. time graph?

(Answer) The graph should show distance on the vertical axis.

(Question) On a distance vs. time graph for an object, a line segment that is sloping upward indicates

(Answer) motion in the positive direction.

Explanation:

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Radioactive iodine (radioiodine) is given to patients with some forms of thyroid cancer in order to destroy the cancer cells. 13

Eva8 [605]

Answer:

I think is D

Explanation:

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4 0

2 years ago

An air-filled parallel-plate capacitor is constructed with a plate area of 0.40 m2 and a plate separation of 0.10 mm. It is then

seropon [69]

Answer:

The charge stored is $Q = 4.25 *10^{-7 } \ C$

The energy stored is $E = 2.55*10^{-6} \ J$

Explanation:

From the question we are told that

The area of the plates is $A = 0.40 \ m^2$

The separation between the plate is $d = 0.10 \ mm =0.0001 \ m$

The potential difference is $V = 12 \ V$

The permitivity of free space is $\epsilon_o = 8.85 *10^{-12} C^2 \cdot N^{-1} \cdot m^2$

The dielectric constant of glass is K = 5.0

Generally the capacitance of this capacitor is

$C = \frac{\epsilon_o * A}{d}$

substituting values

$C = \frac{8.85*10^{-12} * 0.40}{0.0001}$

$C = 3.34 *10^{-8} \ C$

The charge stored is mathematically evaluated as

$Q = CV$

substituting values

$Q = (3.54*10^{-8} * 12)$

$Q = 4.25 *10^{-7 } \ C$

The energy stored is

$E = 0.5 * CV^2$

substituting values

$E = 0.5 * (4.25 *10^{-7} * 12^2)$

$E = 2.55*10^{-6} \ J$

7 0

3 years ago

A 65.0-kg woman steps off a 11.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 4.60 m,

Ganezh [65]

Answer:

2160.26 N.

Explanation:

From the question,

The total energy of the woman = work done by the water.

mg(h+d) = F'×d.......................... Equation 1

m = mass of the the woman, g= acceleration due to gravity, h = height of the platform, d = depth of water reached by the woman, F'= Resistance force exerted on her by the water.

make F' the subject of the equation

F' = mg(h+d)/d............................ Equation 2

Given: m = 65.0 kg, g = 9.8 m/s², h = 11 m, d = 4.6 m.

Substitute into equation 2

F' = 65(9.8)(11+4.6)/4.6

F' = 9937.2/4.6

F' = 2160.26 N.

8 0

3 years ago

A 125kg man buy a 6kg watermelon, a 3kg cantaloupe, and 6kgs of potatoes, he walks home with his purchases in a large bag. His w

Stells [14]

Answer:

350N

Explanation:

Given parameters:

Mass of the man = 125kg

Mass of the watermelon = 6kg

Mass of cantaloupe = 3kg

Mass of potatoes = 6kg

Acceleration = 2.5m/s²

Unknown:

Force required to get home = ?

Solution:

To find this force we use;

Force = mass x acceleration

mass = 125 + 6 + 3 + 6 = 140kg

So;

Net force = 140 x 2.5 = 350N

5 0

3 years ago

The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a

grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

$\sin\theta=\dfrac{3}{5}$

The horizontal component is

$T_{x}=T\cos\theta$

The vertical component is

$T_{y}=T\sin\theta$

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

$\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'$

Put the value into the formula

$0=190\times2+300\times 4-T\sin\theta\times 4$

$T\sin\theta\times 4=380+1200$

$T=\dfrac{1580\times5}{3\times 4}$

$T=658.33\ N$

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

$F_{x}=T\cos\theta$

Put the value into the formula

$F_{x}=658.33\times\dfrac{4}{5}$

$F_{x}=526.66\ N$

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

$F_{y}=F_{b}+F_{w}-T\sin\theta$

Put the value into the formula

$F_{y}=190+300-658.33\times\dfrac{3}{5}$

$F_{y}=95.002\ N$

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

3 0

3 years ago