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3 years ago

how does the charge of a particle affect the direction in wich the particles deflected in a megnetic field

Physics

2 answers:

Brut [27]3 years ago

7 0

<h3>Answer and explanation;</h3>

The type of charge of a particle determines the direction in which the particles will be deflected in a magnetic field such that the negatively charged particles will go toward the positive end of the magnetic field while positively charged particles will go toward the negative end.
This can be explained by the fact that the positive charge is repelled by the positive part of the field, and attracted by the negative end. The negative charge on the other hand will be repelled by the negative end and attracted by the positive end.

shtirl [24]3 years ago

5 0

Negatively charged particles will go toward the positive end of the magnetic field and positively charged particles will go toward the negative end.

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An astronaut on the moon places a package on a scale and finds its weight to be 10. N. () What would the weight of the package

jeka94

Answer:

(a) 61.25 N

(b) 6.25 kg

Explanation:

Weight on moon = 10 N

Acceleration due to gravity on moon = 1.6 m/s^2

Acceleration due to gravity on earth = 9.8 m/s^2

Let m be the mass of the package.

(a) Weight on earth = mass x acceleration due to gravity on earth

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(b) Weight on moon = mass x acceleration due to gravity on moon

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m = 6.25 kg

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

$f=12GHz=12\cdot 10^9 Hz$ is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

So the wavelength of the beam is

$\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m$

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

$y=\frac{m\lambda D}{a}$

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

$y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m$

and so, the diameter is

$d=2y = 750 m$

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

$r=\frac{750 m}{2}=375 m$

So the area is

$A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2$

And since the power is

$P=100 kW = 1\cdot 10^5 W$

The average intensity is

$I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2$

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3 years ago

A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?

lozanna [386]

The answer is: " 44 $\frac{1}{3}$ km " ;
or; write as: " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = " 44 $\frac{1}{3}$ km " ;
or; write as: " 44.333 km " .
___________________________________________________________

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3 years ago

A bike travels at a constant speed for 4.00 m/s for 5.00 seconds. How far does it go

kicyunya [14]

Answer:

20 metres

Explanation:

Speed = distance ÷ time

$s = \frac{d}{t}$