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rewona [7]
3 years ago
14

Question 1(Multiple Choice Worth 3 points)

Chemistry
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

mass molar of  gas (Mw):

Mw = 107 g/mol

Explanation:

∴ m gas = 3.82 g

∴ V gas = 0.854 L

∴ T = 302 K

∴ P = 1.04 atm

ideal gas:

  • PV = RTn

∴ n = m / Mw

⇒ PV = RTm/Mw

⇒ Mw = RTm / PV

⇒ Mw = ((0.082 atm.L/K.mol)*(302 K)*(3.82 g)) / ((1.04 atm)*(0.854 L)

⇒ Mw = 106.51 g/mol ≅ 107 g/mol

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Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]

The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ

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