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umka2103 [35]
3 years ago
9

You have prepared a 1.0 M solution of CaCl2 in the laboratory.

Chemistry
1 answer:
Ratling [72]3 years ago
6 0
It’s C I think and I’m not sure
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How many moles are in sample containing 2.71 x 10^24 atoms of iron?
Deffense [45]

Answer:

4.5 moles

Explanation:

One mole is equal to 6.022 x 10^23 atoms

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Balance the equation by ion electron method
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8 0
2 years ago
Given the reaction _K(s) +_ Cl2(g) → _KCl(s) what is the amount of K, in grams, needed to completely react with 2 moles of Cl2(g
damaskus [11]

Answer:

156.4g K

Explanation:

I'm not sure if it is correct but I think it should be this

What do we know so far?: 2K + 1Cl2 -> 2KCl, 2 mol of Cl2

What are we looking for?: #g of K

What is the ratio of K to Cl2?: 2:1

Set up equation: 2molCl2 x \frac{2mol K}{1 mol Cl2}

Cancel unwanted units: 2 x \frac{2mol K}{1}

Answer we got: 2 x 2mol K = 4mol K

Converting moles to grams: 4 x 39.1 (molar mass of K) = 156.4g K

3 0
3 years ago
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