3 years ago

You have prepared a 1.0 M solution of CaCl2 in the laboratory.

Chemistry

1 answer:

Ratling [72]3 years ago

6 0

It’s C I think and I’m not sure

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When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

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3 years ago

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2 years ago

a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. when placed in water, the block sinks

Art [367]

When the block of iron is placed in water the volume of water that is displaced is 27.0 cm³

<u><em> calculation</em></u>

The volume water that is displaced is equal to volume of block of the iron

volume of block of iron = length x width x height

length= 3 cm

width = 3 cm

height = 3 cm

volume is therefore = 3 cm x 3 cm x 3 cm = 27 cm³ therefore the volume displaced = 27 cm³ since the volume of water displaced is equal to volume of block.

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lukranit [14]

Answer:

0.17907

Explanation:

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What is an element?

Marat540 [252]

B. A pure substance made up of one type of atom

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