In order for a current to be maintained through a conductor a difference in
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a.
The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:
In this circuit, we have
Therefore, the equivalent resistance is
b. 5.8 V, 3.2 V
First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:
where V = 9.00 V and . Substituting,
Now we can calculate the potential difference across each resistor by using Ohm's law again:
<span>H(t) = -16t^2 + vt + s
</span><span>Part A:
</span>Using the given data:
H(t)= -16*t² + 60*t + 82;
Part B:
Put H(t)=0
0<span>= -16*t² + 60*t + 82;</span>
Use the quadratic formula to find t.
See the attachment...'t' is replaced with 'x'.
</span><span>Part A:
</span>Using the given data:
H(t)= -16*t² + 60*t + 82;
Part B:
Put H(t)=0
0<span>= -16*t² + 60*t + 82;</span>
Use the quadratic formula to find t.
See the attachment...'t' is replaced with 'x'.