A. The sound will decrease in volume
Answer:
Yes
Explanation:
Any transparent surface in practical is neither a perfect absorber of electromagnetic waves neither a perfect reflector. Generally all the transparent surfaces reflect some amount of irradiation and the other parts are absorbed and transmitted.
<u>That is given by as relation:</u>

where:
absorptivity which is defined as the ratio of the absorbed radiation to the total irradiation
reflectivity is defined as the ratio of reflected radiation to the total irradiation
transmittivity is defined as the ratio of total transmitted radiation to the total irradiation
Answer:
5.33kg
Explanation:
Given parameters:
Velocity of eagle = 15m/s
Kinetic energy of the eagle = 600J
Unknown:
Mass of the eagle = ?
Solution:
The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical energy.
The formula of kinetic energy is given as;
Kinetic energy =
m v²
where m is the mass, V is the velocity
substitute the parameters in the equation;
600 =
x m x 15²
225m = 1200
m =
= 5.33kg
Answer:
Explanation:
We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for
λ
:
λ
=
v
f
Let's plug in our given values and see what we get!
λ
=
340
m
s
440
s
−
1
λ
=
0.773
m
<span>1.7 rad/s
The key thing here is conservation of angular momentum. The system as a whole will retain the same angular momentum. The initial velocity is 1.7 rad/s. As the person walks closer to the center of the spinning disk, the speed will increase. But I'm not going to bother calculating by how much. Just remember the speed will increase. And then as the person walks back out to the rim to the same distance that the person originally started, the speed will decrease. But during the entire walk, the total angular momentum remained constant. And since the initial mass distribution matches the final mass distribution, the final angular speed will match the initial angular speed.</span>