Which of the following forces best represents an equilibrant force in this system?

A baseball is thrown by the center fielder (from shoulder level) to home plate where it is caught (on the fly at eye level) by t

marishachu [46]

At the highest point of the trajectory the vertical component will have its zero velocity, and the descent caused by the force of gravity will begin.

Since the ball is thrown with a certain speed, the vertical component reaches its highest point (upwards), until returning to the receiver who will receive the ball with the same vertical component but in the opposite direction (downwards).

Therefore the vertical component will have its highest value at launch.

8 0

3 years ago

slab of ice floats on water with a large portion submerged beneath the water surface. The slab is in the shape of a rectangular

n200080 [17]

Answer:

a) $\%V = 87.36\,\%$ , b) $x = 1.248\,m$ , c) $F_{B} = 176488.341\,N$ , d) Six polar bears.

Explanation:

a) The slab of ice is modelled by the Archimedes' Principles and the Newton's Laws, whose equation of equilibrium is:

$\Sigma F =\rho_{w}\cdot g \cdot A \cdot x-\rho_{i}\cdot g\cdot V = 0$

The height of the ice submerged is:

$\rho_{w}\cdot A \cdot x = \rho_{i}\cdot V$

$x = \frac{\rho_{i}\cdot V}{\rho_{w}\cdot A}$

$x = \frac{\left(900\,\frac{kg}{m^{3}}\right)\cdot (20\,m^{3})}{\left(1030\,\frac{kg}{m^{3}} \right)\cdot (14\,m^{2})}$

$x = 1.248\,m$

The percentage of the volume of the ice that is submerged is:

$\%V = \frac{(1.248\,m)\cdot (14\,m^{2})}{20\,m^{3}} \times 100\,\%$

$\%V = 87.36\,\%$

b) The height of the portion of the ice that is submerged is:

$x = 1.248\,m$

c) The buoyant force acting on the ice is:

$F_{B} = \left(1030\,\frac{kg}{m^{3}} \right)\cdot (1.248\,m)\cdot (14\,m^{2})\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F_{B} = 176488.341\,N$

d) The new system is modelled after the Archimedes' Principle and Newton's Laws:

$\Sigma F = -n\cdot m_{bear}\cdot g-\rho_{i}\cdot V \cdot g + \rho_{w}\cdot V\cdot g = 0$

The number of polar bear is cleared in the equation:

$n\cdot m_{bear} = (\rho_{w} - \rho_{i})\cdot V$

$n = \frac{(\rho_{w}-\rho_{i})\cdot V}{m_{bear}}$

$n = \frac{\left(1030\,\frac{kg}{m^{3}} - 900\,\frac{kg}{m^{3}} \right)\cdot (20\,m^{3})}{400\,kg}$

$n = 6.5$

The maximum number of polar bears that slab could support is 6.

8 0

3 years ago

What is the highest temperature ever recorded on earth

Llana [10]

Therefore the world's record high temperature of 134.0°F (56.7°C) is held by Furnace Creek Ranch in Death Valley, California. That global high temperature was attained on July 10, 1913.

4 0

4 years ago

A plumber is trying to fix a clog in a vertical pipe, but does not know how far down in the pipe the clog and the water level is

PIT_PIT [208]

Answer:

the shortest distance to the obstruction is 0.431 m

Explanation:

We can see this system as an air column, where the plumber is open and where the water is closed, in the case when he hears the sound there is a phenomenon of resonance and superposition of waves with constructive interference.

For the lowest resonance we must have a node where the water is and a maximum where the plumber is a quarter of the wavelength

λ = ¼ L

If we are in a major resonance specifically the following resonance. We have a full wavelength plus a quarter of the wavelength

λ = 4L / 3

The general formula is

λ = 4L / n n = 1, 3, 5, 7,…

In addition the wave speed is the product of the frequency by the wavelength

v = λ f

Let's replace

v = (4L / n) f

L = v n / (4 f)

Now we can calculate the depth or length of the air column

If we have the first standing wave n = 1

L = 340 1 / (4 197)

L = 0.431 m

If it is the second resonance n = 3

L = 340 3 / (4 197)

L = 1.29 m

We can see the shortest distance to the obstruction is 0.431 m

5 0

3 years ago

Starting from a location with position vector r1,x =−17.5 m and r1,y=23.1 m , a rabbit hops around for 10.7 seconds with average

lawyer [7]

The kinematics of the uniform motion allows us to find the final position vector

r = (-41.575 i + 42.253 j) m

Given parameters

the starting position x = -17.5 m y = 23.1 m
jump time t = 10.7 s
The average velocities vₓ = -2.25 m / s and v_y = 1.79 m / s

to find

the final position

The uniform motion occurs when the velocity of the bodies is constant, in this case the relationship can be used for each axis

v = $\frac{x-x_o}{t}$

x = x₀ + v t

Where vₓ it is the velocity, x the displacement, x₀ the initial position and t the time

Let's set a reference system with the horizontal x-axis. Regarding which we carry out the measurements

X axis

we look for the final position

x = x₀ + vₓ t

x = -17.5 -2.25 10.7

x = -41.575 m

Y Axis

we look for the final position

y = y₀ + v_y t

y = 23.1 + 1.79 10.7

y = 42.253 m

In conclusion, using the kinematics of uniform motion, find the final position vector

r = (-41.575 i + 42.253 j) m

learn more about uniform motion here:

brainly.com/question/17036013

3 0

3 years ago