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3 years ago

Why does laser beam might appear blue and another laser beam might appear red?

2 answers:

6 0

A laser emits light at one single frequency (one single wavelength).
But not all lasers emit the same one.

The frequency (wavelength) that comes out of a laser depends on the
material that's doing the 'lasing' ... different material fabricated into a
laser diode ==> different wavelength in the output.

Many lasers, but not all, emit a frequency (wavelength) that's in the visible
range, and a single given laser may emit red, orange, yellow, green, blue,
or violet light. Lasers of other designs emit at frequencies outside the visible
range, in the microwave, infrared, or ultraviolet.

Alenkasestr [34]3 years ago

4 0

The red laser will have a hotter temperature than the blue, so it is red because it is hot
hope this helps!!!

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At a constant pressure, 10 L of a gas at 546 K is cooled to 273 K

lisabon 2012 [21]

Answer:

5 L

Explanation:

Ideal gas law:

PV = nRT

If P, n, and R are constant, then:

n₁R/P₁ = n₂R/P₂

Using ideal gas law, we can rewrite this as:

V₁/T₁ = V₂/T₂

This is known as Charles' law.

Plugging in values:

10 L / 546 K = V / 273 K

V = 5 L

8 0

3 years ago

Match the sentences in Column A based on whether they describe radio waves, visible light waves, or both (Column B). Column A 1.

Andrew [12]

1. They’re invisible - RADIO WAVES

2. They have colors. - VISIBLE LIGHT WAVES

3. They’re used to learn about dust and gas clouds. - BOTH

4. They can travel in a vacuum. - BOTH

5. They’re used to find the temperature of stars. - VISIBLE LIGHT WAVES

6. They have energy. - BOTH

8 0

3 years ago

Read 2 more answers

g A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is

oksian1 [2.3K]

Answer:

velocity of girl with respect to surface of ice 1.154 m/s

Explanation:

Plank Mass , M = 150 kg

Girl Mass , m = 45 kg

velocity of the girl with resect to plank, v1 = 1.50 m/s

velocity of the plank + girl = v2

from the conservation of momentum

Momentum (plank+girl) = - momentum of the girl

(M+m)v2 = -mv1

v2 = -(45 kg)/(195 kg) * 1.50

v2 = -0.346 m/s

velocity of girl with respect to surface of ice =

v1+v2 = 1.50 + (-0.346) = 1.154 m/s

4 0

3 years ago

Read 2 more answers

Two identical conducting spheres, having charges of opposite sign, attract each otherwith a force of 0.108 n when separated by 5

lisov135 [29]

Let's start from the final situation. After the two spheres are connected with the conducting wire, the total charge distributes equally between the two spheres (because they are identical). We can call the charge on each sphere $Q/2$ , with Q being the total charge.
The electrostatic force in this situation is 0.0360 N, so we can write
$F=k \frac{( \frac{Q}{2} )^2}{r^2}$
where k is the Coulomb's constant and $r=50.0 cm=0.50 m$ is the separation between the two spheres. Using F=0.0360 N, we can find the value of Q, the total charge shared between the two spheres:
$Q= \sqrt{ \frac{4Fr^2}{k} } = \sqrt{ \frac{4(0.0360 N)(0.50 m)^2}{8.99 \cdot 10^9 Nm^2C^{-2}} }=2.0 \cdot 10^{-6}C$

Now let's go back to the initial situation, before the conducting wire was attached; in this situation, the two spheres have a charge of $q_1$ and $q_2$ , whose sum is Q:
$Q=q_1 + q_2$
The electrostatic force between the two spheres in the initial situation is:
$F=k \frac{q_1 q_2}{r^2}$
And since we know F=0.108 N, we find
$q_1 q_2 = \frac{Fr^2}{k} = \frac{(0.108 N)(0.50 m)^2}{8.99 \cdot 10^9 N m^2 C^{-2}}=3.0 \cdot 10^{-12} C$
But the problem tells us that the two spheres have charges of opposite sign, so we must put a negative sign:
$-3.0 \cdot 10^{-12} C = q_1 q_2$

So now we have basically a system of 2 equations:
$2.0 \cdot 10^{-6} C = Q = q_1 + q_2$
$-3.0 \cdot 10^{-12} C = q_1 q_2$
If we solve it, we find the initial charge on the two spheres:
$q_1 = -1 \cdot 10^{-6}C$
$q_2 = +3 \cdot 10^{-6 } C$

6 0

3 years ago

You are asked to design a spring that will give a 1020 kg satellite a speed of 2.25 m/s relative to an orbiting space shuttle. Y

julsineya [31]

Answer:

(a) 2.45×10⁵ N/m

(b) 0.204 m

Explanation:

Here we have that to have a velocity of 2.25 m/s then the relationship between the elastic potential energy of the spring and the kinetic energy of the rocket must be

Elastic potential energy of the spring = Kinetic energy of the rocket

$\frac{1}{2} kx^2 = \frac{1}{2} mv^2$