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The average velocity can be calculated using the formula:
v = d / t
For the 1st car, the velocity is calculated
as:
v1 = 8.60 m / 1.80 s = 4.78 m / s
While that of the 2nd car is:
v2 = 8.60 m / 1.66 s = 5.18 m / s
Now we can solve for the acceleration using the formula:
v2^2 = v1^2 + 2 a d
Rewriting in terms of a:
a = (v2^2 – v1^2) / 2 d
a = (5.18^2 – 4.78^2) / (2 * 8.6)
a = 0.23 m/s
Therefore the train has a constant acceleration of about
0.23 meters per second.
Answer:
a = 0.701 m / s²
Explanation:
As the game is spinning the acceleration is centripetal
a = v² /r
The park system after a small period of acceleration goes at a constant speed, for which we can use the relations of the uniform motion
v = d / t
the distance of a circle is
d = 2π r
we substitute
a = (2π r / t) ² / r
a = 4 pi² r / t²
let's calculate
a = 4 pi² 12 / 26²
a = 0.701 m / s²
Answer:
velocity in which the space described varies from instant to instant, either increasing or decreasing in the former case called accelerated velocity
Explanation:
I hope this helps :)...
