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irga5000 [103]
3 years ago
13

Which vector is the sum of vectors a and b

Physics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

C

Explanation:

Vector A points up

Vector B points right

The combination must be both up and right which is C

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Satellite A has an orbital radius 3.00 times greater than that of satellite B. Satellite B's orbital period around Earth is 120
igomit [66]

Answer:

To find the circumference (orbit) of an object, you use Pi x Diameter. 

As you have the circumference of B, you divide it by Pi to get the Diameter. 

So 120 divided by 3.141592654 = 38.2 minutes for the Diameter. 

As' radius and Diameter will be 3x greater than B. 

38.2 x 3 = 114.6 

To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

THNXX :)

7 0
3 years ago
What is the awnser to Blank occurs when a substance changes from a liquid to a gas
PolarNik [594]
Evaporation (or another word to use is water vapor.)
3 0
3 years ago
What is the velocity of the particle when its acceleration is zero?
Zigmanuir [339]
Its velocity would be constant 
3 0
3 years ago
A square sheet of rubber has sides that are 20 cm long. If you stretch it so that the area of the rubber is four times larger, h
oee [108]

Answer:

400

Explanation:

Trust me its correct

7 0
3 years ago
Read 2 more answers
Two charged spheres are 20 cm apart and exert an attractive force of 8 x 10-9 n on each other. What will the force of attraction
Pavel [41]

Answer:

3.2\cdot 10^{-8} N

Explanation:

The inital electrostatic force between the two spheres is given by:

F=k\frac{q_1 q_2}{r^2}

where

F=8\cdot 10^{-9} N is the initial force

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

r'=\frac{r}{2}

Therefore, the new electrostatic force will be

F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F

So the force has increased by a factor 4. By using F=8\cdot 10^{-9} N, we find

F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N

6 0
3 years ago
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