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Gennadij [26K]
4 years ago
15

HELPPPPP FASSSTTTTT 30 POINTS

Chemistry
2 answers:
sweet [91]4 years ago
7 0

Soil is built up of clastic particles, organics, and clay while sand is a combination of rocks, minerals, and fragments of rotting shells.

Soil particles are larger in size and mass together, Sand particles are tinier and individual.

<u>Explanation:</u>

So, the soil is weaker than sand particles. When we mix soil and sand into the water, we acknowledge that soil particles somewhat settle at the bottom while designing parts mixed into water. Sand is almost heavier than water so it settles down at the base.

Soil particles settle faster and will be on the bottom while the sand particles will be on top. And no this is not a great method to define particle size distribution.

MrMuchimi4 years ago
5 0

Answer:

1. The larger and heavier particles settled first and settled at the bottom.

2. Gravel is settled at the very bottom because it is heavier than sand and clay.  

3. No, because each layer has smaller and lighter particles in it.  

4. No, because the amount of each type of particle is different in every location.  

Explanation:

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Kilogram is a unit of volume true or false
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4 years ago
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if 3.0 grams of aluminum and 6.0 grams of bromine react to form AlBr3, how many grams of product would theoretically be produced
Gelneren [198K]
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.

2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
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n - amount of substance.
M - molar mass.

4 0
3 years ago
3.
asambeis [7]

Answer:

zinc forms more than one ion

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