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3 years ago

HELPPPPP FASSSTTTTT 30 POINTS

2 answers:

7 0

Soil is built up of clastic particles, organics, and clay while sand is a combination of rocks, minerals, and fragments of rotting shells.

Soil particles are larger in size and mass together, Sand particles are tinier and individual.

<u>Explanation:</u>

So, the soil is weaker than sand particles. When we mix soil and sand into the water, we acknowledge that soil particles somewhat settle at the bottom while designing parts mixed into water. Sand is almost heavier than water so it settles down at the base.

Soil particles settle faster and will be on the bottom while the sand particles will be on top. And no this is not a great method to define particle size distribution.

MrMuchimi3 years ago

5 0

Answer:

1. The larger and heavier particles settled first and settled at the bottom.

2. Gravel is settled at the very bottom because it is heavier than sand and clay.

3. No, because each layer has smaller and lighter particles in it.

4. No, because the amount of each type of particle is different in every location.

Explanation:

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Calculate the maximum numbers of moles and grams of H₂S that can form when 158 g of aluminum sulfide reacts with 131 g of water:

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Mass of aluminium sulfide is 158g

Mass of water is 131g

The chemical reaction: $Al_{2}S_{3} +H_{2}O _\to Al(OH)_{3} + H_{2}S$

First, balance the chemical equation

$Al_{2}S_{3} + 6H_{2}O \to 2Al(OH)_{3} + 3H_{2}S$

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Moles of $H_{2}S$ formed = 7.26 mol $H_{2}O \times \frac{3 mol H_{2}S }{6 mol H_{2} O} }$

Th liming reactant is $Al_{2}S_{3}$ beacuse the mass of $Al_{2}S_{3}$ forms less product than water. Therefore, the maximum number of moles of $H_{2}S$ is 3.15 mol. We know that molar mass of $H_{2}S$ is 34.10g/mol. So, the maximum mass of $H_{2}S$ formed is,

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Now, multiplying the number of moles of $Al_{2}S_{3}$ by the molar ratio between $Al_2S_3$ and $H_2O$ which is 6mol $H_2O/1mol$ $Al_2S_3$ we get the number of moles of $H_2O$ reacted.

Moles of $H_2O$ reacted = 1.05 mol $Al_{2}S_3 \times \frac{6 mol H_2O}{1 mol Al_2S_3}$

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The mass of $H_2O$ is,

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