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frez [133]
4 years ago
11

A black rooster mates with a white hen. Based on their genotypes, the chance that the offspring will be checkered is 100 percent

. What is the rooster’s genotype? What is the hen’s genotype? The rooster genotype is . The hen’s genotype is .
Chemistry
2 answers:
jeka57 [31]4 years ago
7 0

Answer:

Answer: BB is rooster.

bb is hen

Explanation:

zheka24 [161]4 years ago
6 0

Answer: BB is rooster.

bb is hen

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El plomo y el yodo forman dos compuestos. En uno, el porcentaje de en masa de plomo es del 44,94% y en el otro es de 62,02%. Cal
nikdorinn [45]

Answer:

0.8162 gramos de plomo por gramo de yodo

1.633 gramos de plomo por gramo de yodo

Explanation:

Asumiendo una base de 100 gramos para cada compuesto:

Primer compuesto:

Gramos plomo: 44.94g

Gramos de yodo: 100-44.94g = 55.06g

Así, la masa de plomo por gramos de yodo para el primer compuesto es:

44.94g plomo / 55.06g Yodo =

<em>0.8162 gramos de plomo por gramo de yodo</em>

<em></em>

Segundo compuesto:

Gramos plomo: 62.02g

Gramos de yodo: 100-62.02g = 37.98g

La masa de plomo por gramos de yodo para el segundo compuesto es:

62.02g plomo / 37.98g Yodo =

<em>1.633 gramos de plomo por gramo de yodo</em>

8 0
3 years ago
What percentage of carpet is calcium carbonates?
e-lub [12.9K]

Answer:

the percentage of carpet is calcium carbonates is 12.456734190

5 0
3 years ago
How many moles of calcium (Ca) atoms are there in 77.4 g of Ca?
Vinvika [58]
Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
8 0
3 years ago
Read 2 more answers
What is the mass, in grams, 200mL of liquid with a density of 1.4g/mL
Tcecarenko [31]

The mass of the liquid is 280 g.

Mass = 200 mL × (1.4 g/1 mL) = 280 g

6 0
3 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
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