All categories

3 years ago

I need help asap please help me

Chemistry

2 answers:

Sindrei [870]3 years ago

7 0

Traits is the right answer

poizon [28]3 years ago

4 0

I think the correct answer is traits. Please brainiest me! :)

You might be interested in

How many grams of NaCl are in 0.50 moles of NaCl?

Semmy [17]

Hope this helps! 29.221385

7 0

3 years ago

Will mark branliest. Calculating percent yield: For the reaction Cu + 2AgNO3 → Cu(NO3)2 + 2 Ag, adding 127 grams of copper to lo

pishuonlain [190]

Percent yield = (Actual Yield/ Theoretical Yield) x 100

Given, Actual Yield of silver = 410 grams

Given, mass of copper = 127 g

Atomic mass of copper = 63.546 amu

Formula: Moles = mass / atomic mass

Moles of copper = 127 g/ 63.546 amu = 1.998 mol

Based on the given balanced chemical reaction, the molar ratio between Cu: Ag is 1:2

So 1.998 mol of copper should yield (2 mol Ag/ 1 mol Cu) x 1.998 mol of Cu = 3.996 mol

Calculated mol of Ag = 3.996 mol

Atomic mass of silver = 107.8682 amu

Mass of silver = moles x atomic mass = 3.996 mol x 107.8682 amu = 431 g

Based on the math, the theoretical yield = 431 g

Percent yield of silver = (410g/431g) x 100 = 95. 13%

The answer is 95. 13%

8 0

3 years ago

A stable community that no longer goes through ecological changes?

Tanya [424]

This is called a climax community.

6 0

3 years ago

What is 0.05 kg mass in milligrams?

liberstina [14]

Convert 0.05 Kilograms to Milligrams (kg to mg) with our conversion calculator and conversion tables. To convert 0.05 kg to mg use direct conversion formula below.
0.05 kg = 50000 mg.
You also can convert 0.05 Kilograms to other Weight (popular) units.

3 0

3 years ago

Read 2 more answers

A 2.89 g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chlo

dsp73

Answer:

58.0 g/mol

Explanation:

The reaction that takes place is:

MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂

First we calculate how many moles of silver chloride were produced, using its molar mass:

6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl

Then we convert AgCl moles into MCl₂ moles, using the stoichiometric ratio:

0.0447 mol AgCl * $\frac{1molMCl_2}{2molAgCl}$ = 0.0224 mol MCl₂

Now we calculate the molar mass of MCl₂, using the original mass of the sample:

2.86 g / 0.0224 mol = 127.68 g/mol

We can write the molar mass of MCl₂ as:

Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2

127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2

Finally we calculate the molar mass of M:

Molar Mass of M = 57 g/mol

The closest option is 58.0 g/mol.

6 0

3 years ago