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Vsevolod [243]
3 years ago
12

Which choice represents a pair of resonance structures? note that lone pairs have been omitted for clarity. hints which choice r

epresents a pair of resonance structures? note that lone pairs have been omitted for clarity. o=n−cl and n=o−cl n≡c− and n≡c−h o−s=o and o=s−o h−h and br−br?
Chemistry
1 answer:
loris [4]3 years ago
6 0
Th choice which represent a pair of resonance structures is O - N =O  and O = N - O. 
A resonance pair is another mean of drawing the Lewis structure of a compound. Equivalent Lewis structures are called resonance form. Resonance form is used to spot delocalized electrons; this is done by comparing the electron locations in the two resonance form. If a pair appear in one place in one form and the other pair form and place are different, then the pair is delocalized. <span />
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What are three applications of the<br>coal ​
labwork [276]

Three uses of coal:

1. Electricity generation

2. Steel production

3. Cement manufacturing and as a liquid fuel

Hope it helps!

3 0
3 years ago
The momentum of an object is in the same direction as its
fredd [130]
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8 0
3 years ago
If the human body contains about 50 deciliters of blood, and the blood has about 15 grams of hemoglobin per deciliter, and all o
Tcecarenko [31]

Answer:

The blood will contain 750 grams of O2

Explanation:

Volume of blood in the human body = 15 deciliters

Mass of hemoglobin per deciliter of blood = 15 grams

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Since all the hemoglobin molecules are saturated with O2, mass of O2 in the blood will be the same as mass of hemoglobin molecules in the blood.

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6 0
3 years ago
Read 2 more answers
Help me nowww please and thanks
kati45 [8]

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4 0
3 years ago
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The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of
taurus [48]

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

7 0
3 years ago
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