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aksik [14]
3 years ago
5

Propanoic acid has a boiling point of 141 °C, propanamide has a boiling point of 213 °C, and propanal has a boiling point of 48

°C. Rationalize the differences in boiling point between these three compounds.
Chemistry
1 answer:
deff fn [24]3 years ago
4 0

Explanation:

  • As it is given that boiling point of propanamide is very high. So, reason for this is that easy formation of hydrogen bonds which are strong enough that we have to provide large amount of heat to break it.

As in -NH_{2}, the hydrogen atoms which are present are positive in nature. Due to this they are able to form hydrogen bonds with the neighboring oxygen atom.

Hence, these bonds are so strong that high heat needs to given to break them.

  • A propanoic acid contain carboxylic group as the functional group. So, this group is also able to form hydrogen bonding as it forms a hydrogen bond between an acid group and hydroxyl group of neighboring molecule.

Hence, it will also require high heat to break the bond due to which there will be increase in boiling point.

  • In propanal, there is presence of aldehyde functional group and three carbon atoms chain which will not form strong bonding with the hydrogen atom of CHO. Due to this there will exist weak Vander waal's force that is not at all strong enough.

As a result, less energy will be needed to break the bonds in propanal. Hence, it has very low boiling point.

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1) Answer is: there are 9.04 moles of the hydrogen in 4.52 mol of the water.

n(H₂O) = 4.52 mol; amount of the water molecules.

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n(H₂O) : n(H) = 1 : 2.

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2) Answer is: there are 25.29 moles of the hydrogen in 8.43 mol of the ammonia (NH₃).

n(NH₃) = 8.43 mol; amount of the ammonia molecules.

In one molecule of the ammonia, there are three hydrogen atoms.

n(NH₃) : n(H) = 1 : 3.

n(H) = 3 · n(NH₃).

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3) Answer is: there are 0.408 moles of the hydrogen in 0.102 mol of the hydrazine (N₂H₄).

n(N₂H₄) = 0.102 mol; amount of the hydrazine molecules.

In one molecule of the hydrazine, there are four hydrogen atoms.

n(N₂H₄) : n(H) = 1 : 4.

n(H) = 4 · n(N₂H₄).

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4) Answer is: there are 770 moles of the hydrogen in 35.0 moles of the decane (C₁₀H₂₂).

n(C₁₀H₂₂) = 35.0 mol; amount of the decane molecules.

In one molecule of the decane, there are twenty two hydrogen atoms.

n(C₁₀H₂₂) : n(H) = 1 : 22.

n(H) = 22 · n(C₁₀H₂₂).

n(H) = 22 · 35.0 mol.

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<em>If you got helped from this answer please give me brainliest and if you didn't get what you were looking for then please tell me in the comments</em>

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