Answer:
384.6 m
Explanation:
The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:
where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and is the distance of the runway, which we care looking for
Answer:
Explanation:
We have given the rest mass of SPARTYON = 945 times of mass of electron
We know that mass of electron
So mass of SPARTYON
Speed of light
According to Einstein equation energy is given by
Now according to planks's rule
Energy is given by
, here h is plank's constant
So
Answer: 4.6 years
Explanation:
According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis
(size) of its orbit”:
</em>
<em />
(1)
However, if is measured in Earth years, and
is measured in astronomical units (unit equivalent to the distance between the Sun and the Earth), equation (1) becomes:
(2)
Knowing and isolating
from (2):
(3)
(4)
Finally:
This is Ceres' orbital period
The question is incomplete. Here is the complete question.
A current in the long, straight wire, which lies in the plane of rectangular loop, that also carries a current, as shown in the figure.
Find the magnitude of the net force exerted on the loop by the magnetic field created by the long wire. Answer in units of N.
Answer: Net Force = N
Explanation: Force and Magnetic field are related through the following formula:
F = I.L.B.sinθ
Magnetic field (B) in a straight long wire is given by
in which
is permeability of free space and is
T.m/A
I is current in the wire;
r is distance to the wire;
Examining the square loop and using the right hand rule, the top, which we will name it F₂, and the bottom, named F₄, have angle θ = 0, giving sin(0) = 0 and therefore, F₁ = F₃ = 0.
So, for the net force, the relevant forces will be on the sides parallel to the wire.
For the other forces, angle is 90°, sin(90°) = 1, then:
F = I.L.B
Replacing magnetic field:
F =
Note: The side closest to the wire is F₁, while the farthest is F₃.
Note2: As the constant unit is in meters, distance and length of side of the square loop are also in meters.
Calculating forces:
F₁ =
F₁ = N
Current in F₃ is flowing thoruhg the negative side of the referential, so:
F₃ =
F₃ = N
<u>Net</u> <u>force</u> is total force:
The total force acting on the square loop is N.
