a. t=0.553 s
b. vox(horizontal speed) = 3.62 m/s
<h3>Further explanation</h3>
Given
h = 1.5 m
x = 2 m
Required
a. time
b. vo=initial speed
Solution
Free fall motion
a. h = 1/2 gt²(vertical motion=h=voyt+1/2gt²⇒voy = 0)
t = √2h/g
t = √2.1.5/9.8
t=0.553 s
b. x=vox.t(horizontal motion)
vox=x/t
vox=2/0.553
vox=3.62 m/s
The decrease in velocity is called deceleration or negative acceleration.
Hope i helped... If you need anything else ask me! :)
Answer:
when electron emit the radiations it means it jumped to the lower energy level from higher energy level.
Explanation:
When electron jump into lower energy level from high energy level it loses the energy.
The process is called de-excitation.
Excitation:
When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.
De-excitation:
When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.
Answer:
7,9,11
Explanation:
this is because water includes 0H, which would mean that it is more than 6
Hello!
When HI is added, the buffer reacts in the following way:
1) Neutralizing of the Acid:
HI + NH₄OH → NH₄I + H₂O
2) Dissociation of the salt of a weak acid:
NH₄I → NH₄⁺(aq) + I⁻ (aq)
3) Dissociation of a weak acid to form H₃O⁺ (very little):
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.
Have a nice day!
