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krok68 [10]
4 years ago
9

How many nanometers are in 0.0006245101 km?

Chemistry
1 answer:
maw [93]4 years ago
5 0

Answer:

624510100

Explanation:

Doing a conversion factor:

0,0006245101[km]*\frac{1000[m]}{1 km} *\frac{1x10^{9} nanometer}{1 m} =624510100 [nanometer]

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For the reaction below, determine the standard free energy change, δg o. cu(s) + sn2+(aq) → cu2+(aq) + sn(s) e o cell =–0.48 v v
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Answer:

92.6 kJ.

Explanation:

<em>∵ ΔG°rxn = - nFE°cell,</em>

Where, ΔG°rxn is the standard free energy change (J).

n is the no. of electrons in the reaction (n =2).

F is Faraday constant (C/mol) (F = 96500 C/mol).

E°cell is the standard cell potential (E°cell = - 0.48 V).

<em>∴ ΔG°rxn = - nFE°cell </em>= - (2)(96500 C/mol)(- 0.48 V) = <em>92640 J = 92.64 kJ.</em>

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3 years ago
In the US, nutritional energy is reported in Calories (Cal). One nutritional Calorie is equal to one kilocalorie (kcal). If a fo
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2.500 × 10⁵ cal

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What properties do atoms of the same element share? Select all that apply.
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How many milliliters of a 1M nitric acid solution are required to prepare 60mL of 6.7M solution?
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Answer:

the number of milliliters of a 1M is 402mL

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