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krok68 [10]
3 years ago
9

How many nanometers are in 0.0006245101 km?

Chemistry
1 answer:
maw [93]3 years ago
5 0

Answer:

624510100

Explanation:

Doing a conversion factor:

0,0006245101[km]*\frac{1000[m]}{1 km} *\frac{1x10^{9} nanometer}{1 m} =624510100 [nanometer]

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If you have a 12.0 gram steel ball at sea level and then take it up to mt. Fuji what will change?
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The air pressure. the air pressure increases as the altitude an object is at increases.
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2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g
cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ----------  ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 =  12 / 5

moles of CO2 = 2.4 moles

So, molar  mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A


Hope that helps!

8 0
3 years ago
Which substance is a base? HCOOH RbOH H2CO3 NaNO3
Alex Ar [27]

Answer:

RbOH

Explanation:

For this question, we have to remember what is the definition of a base. A base is a compound that has the <u>ability to produce hydroxyl ions</u> OH^-, so:

AOH~->~A^+~+~OH^-

With this in mind we can write the <u>reaction for each substance:</u>

HCOOH~->~HCOO^-~+~H^+

RbOH~->~Rb^+~+~OH^-

H_2CO_3~->~CO_3^-^2~+~2H^+

NaNO_3~->~Na^+~+~NO_3^-

The only compound that fits with the definition is RbOH, so this is our <u>base</u>.

I hope it helps!

6 0
3 years ago
Read 2 more answers
How many electrons are in the highest occupied energy level of a nuetral silicon atom?
Ludmilka [50]
A). 4
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3 0
3 years ago
How many grams are in 0.220 mol of Ne?
kumpel [21]

Answer:

4.44 g Ne

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.220 mol Ne

<u>Step 2: Identify Conversions</u>

Molar Mass of Ne - 20.18 g/mol

<u>Step 3: Convert</u>

<u />0.220 \ mol \ Ne(\frac{20.18 \ g \ Ne}{1 \ mol \ Ne} ) = 4.4396 g Ne

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.4396 g Ne ≈ 4.44 g Ne

3 0
3 years ago
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