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3 years ago

Complete the nuclear reaction.*

Chemistry

1 answer:

irina [24]3 years ago

5 0

$\boxed {_{-1}^0e}$

Explanation:

$\huge _{53}^{125}I\rightarrow _{54}^{125}Xe+\boxed {_{-1}^0e}$

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2074 Set B Q.No. 1 What mass of nitrogen will be requires

timurjin [86]

140 g of nitrogen (N₂)

Explanation:

We have the following chemical equation:

N₂ + 3 H₂ -- > 2 NH₃

Now, to find the number of moles of ammonia we use the Avogadro's number:

if 1 mole of ammonia contains 6.022 × 10²³ molecules

then X moles of ammonia contains 6.022 × 10²⁴ molecules

X = (1 × 6.022 × 10²⁴) / 6.022 × 10²³

X = 10 moles of ammonia

Taking in account the chemical reaction we devise the following reasoning:

If 1 mole of nitrogen produces 2 moles of ammonia

then Y moles of nitrogen produces 10 moles of ammonia

Y = (1 × 10) / 2

Y = 5 moles of nitrogen

number of moles = mass / molecular weight

mass = number of moles × molecular weight

mass of nitrogen (N₂) = 5 × 28 = 140 g

Learn more about:

Avogadro's number

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3 years ago

stiks02 [169]

Answer:

An organ is a part of the body that carries out its main function. Most organs are made out of tissues.

Explanation:

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2 years ago

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What does the enthalpy of reaction measure?

Gnesinka [82]

The heat released/absorbed by a reaction that occurs at constant pressure.

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2 years ago

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Explain how errors in measurements can affect the safety of products?

disa [49]

Answer:

Its can affect the safety of products by, for example, if you put raw chicken in the oven and don't cook it for long enough, it can make you sick

Explanation:

4 0

3 years ago

Consider two solutions, the first being 50.0 mL of 1.00 M CuSO4 and the second 50.0 mL of 2.00 M KOH. When the two solutions are

kolbaska11 [484]

Explanation:

Molarity of copper sulfate solution = 1.00 M

Volume of the copper sulfate solution = 50.0 mL = 0.050 L

Moles of copper sulfate = n

$1.00M=\frac{n}{0.050 L}$

n = 0.050 L × 1.00 M= 0.050 mol

1 mol of copper sulfate has 1 mol of copper . Then 0.050 mol of copper sulfate has :

$1\times 0.050 mol=0.050 mol$ of copper

a) Mass of 0.050 moles of copper = 0.050 mol × 63.5 g/mol =3.175 g

b) The identity of the compound which formed after the reaction is copper hydroxide.

c) The complete equation for the reaction that occurs when copper sulfate and potassium hydroxide are mixed:

$CuSO_4(aq)+2KOH (aq)\rightarrow Cu(OH)_2(s)+K_2SO_4 (aq)$

d) $CuSO_4(aq)\rightarrow Cu^{2+}(aq) +SO_{4}^{2-}(aq)$ ..[1]

$KOH (aq)\rightarrow 2K^+(aq) +OH^-(aq)$ ..[2]

$Cu^{2+}(aq) +SO_{4}^{2-}(aq)+2K^+(aq) +2OH^-(aq)\rightarrow Cu(OH)_2(s)+SO_{4}^{2-}(aq)+2K^+(aq)$

Common ion both sides are removed. The net ionic equation is given as:

$Cu^{2+}(aq) +2OH^-(aq)\rightarrow Cu(OH)_2(s)(aq)$

e) Volume of solution after mixing of both solution,V= 50 mL + 50ml = 100 mL

Mass of final solution ,m= 1 mL

Density of solution ,d= 1 g/mL (same as pure water)

$m=d\time V=1 g/ml\times 100 mL = 100 g$

Heat capacity of the solution = c = 4.186 J/g°C (same as pure water)

Change in temperature of the solution,ΔT = 27.7 °C- 21.5 °C=6.2°C

$Q=mc\Delta T$

$Q=100 g\times 4.186 J/g ^oC\times 6.2^oC=2595.32 J=2.595 kJ$

Enthalpy of the reaction = ΔH = $\frac{Q}{\text{Moles of copper}}$

ΔH = $\frac{2.595 kJ}{0.050 mol}=51.90 kJ/mol$

The ΔH for the reaction that occurs on mixing is 51.90 kJ/mol.

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2 years ago