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ki77a [65]
4 years ago
6

Which of the following tests could be safely used to distinguish a strong base from a weak base?

Chemistry
2 answers:
vova2212 [387]4 years ago
5 0
Strong base will completely ionize in water while the weak acid will not
pashok25 [27]4 years ago
3 0

its D on plato :)) I just took the test and got it right

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Explanation:

6 0
3 years ago
From left to right in the periodic table does in get larger or smaller
Paul [167]
Atomic size gradually decreases from left to right across a period of elements.
6 0
3 years ago
Explain what is water of crystallization​
ArbitrLikvidat [17]

Explanation:

In chemistry, water(s) of crystallization or water(s) of hydration are water molecules that are present inside [crystal]s. Water is often incorporated in the formation of crystals from aqueous solutions. ... Water of crystallization can generally be removed by heating a sample but the crystalline properties are often lost

3 0
3 years ago
A set of headphones produces sounds that cancel out sound waves from the
Basile [38]

Answer:

C. Destructive interference

Explanation:

<em>Destructive interference</em> is when there are two waves <u>with the same frequency</u>, and the peaks of one wave (the highest points) line up with the valleys (the lowest points) of the second one.

Constructive interference would cause the sound to be louder.

Absorption and reflection are interactions that would not take into account the fact that the headphones produce sounds.

4 0
3 years ago
The block in this illustration is floating in water, which has a density of 1.00 g/cm3 .What is a good estimate of the density o
miss Akunina [59]

Answer : The density of the block is estimated to be, 0.30g/cm^3.

Explanation :

Density of the water, \rho_w=1.0 g/cm^3

As we know that,

Buoyant force = \rho\times volume\times g

where,

g = gravitational acceleration

volume of the block = v

density of the block = \rho_o

Weight of the Block = Buoyant force exerted by water

\rho_o\times v\times g=\rho_w\times 30\%\text{ of volume of block}\times g

\rho_o\times v\times g=\rho_w\times 0.30v\times g

\rho_o\times v\times 9.8 m/s^2=1 g/cm^3\times 0.30v\times 9.8 m/s^2

\rho_o=0.30 g/cm^3

Thus, the density of the block is estimated to be, 0.30g/cm^3.

6 0
3 years ago
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