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3 years ago

A race car starts from rest and accelerates uniformly to 69 mph in 4.5 s.

1 answer:

5 0

For this question we should apply
a = v^2 - u^2 by t
a = 69 - 0 by 4.5
a = 69 by 4.5
a = 15.33
a = 6.85 m/s^2

If the answer in option is near to answer then , you can mark it as correct.
.:. The acceleration is 6.9 m/s^2

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A 70.0-kg astronaut pushes to the left on a spacecraft with a force F in "gravity-free" space. The spacecraft has a total mass o

goldenfox [79]

Answer:

$a_2=-0.00252\ m/s^2$

Explanation:

Given that,

Mass of the astronaut, m = 70 kg

Mass of the spacecraft, $m'=10^4\ kg$

Acceleration of the astronaut, $a_1=0.36\ m/s^2$

To find,

The magnitude of the acceleration of the spacecraft.

Solution,

The force acting on the astronaut is given by :

$F=m\times a_1$

$F=70\ kg\times 0.36\ m/s^2=25.2\ N$

During the push, the astronaut accelerates as a result a reaction force will also act on the spacecraft. Let $a_2$ is the acceleration of the spacecraft. It can be calculated as :

$a_2=\dfrac{-F}{m}$ (reaction force)

$a_2=\dfrac{-25.2}{10^4}$

$a_2=-0.00252\ m/s^2$

Therefore, the magnitude of the acceleration of the spacecraft is $0.00252\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago

How does wind power generate electricity?

viktelen [127]

I think the answer is A!

3 0

4 years ago

Convert 130 pounds (lbs) to kilograms (kg) where 2.2 lbs = 1 kg. Round to the nearest whole

WARRIOR [948]

Answer:

Explanation:

You have the formula, so I dont think I have to explain, but just do 130 divided by 2.2 and you'll get 59

6 0

4 years ago

Read 2 more answers

Marcus tries to move a refrigerator but can't. Has he done work?

katen-ka-za [31]

Answer:

Explanation:

Even if the refrigerator did not move he still used energy to try to push it it's just his energy wasnt stronger than the refrigerator's energy

3 0

3 years ago

When an electron jumps from high-to low-energy levels:

AysviL [449]

Answer:

B. A wave of visible light is produced.

Explanation:

The visible light spectrum is in the centre of the Electromagnetic Spectrum, so any time an electron jumps from high to low levels of radiation, it has to cross through the visible spectrum.

I hope this is correct, and as always, I am joyous to assist anyone at any time.

5 0

4 years ago