Use the formula for distance dropped from rest:
D = 1/2 a t^2 .
With no air resistance, you get about 8.8 sec.
I'm pretty sure you can fill in the missing work.
Answer:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
Explanation:
The graph shown in the figure is a velocity-time graph, which means that:
- On the x-axis, the time is plotted
- On the y-axis, the velocity is plotted
Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
From the graph, it would be possible to infer additional information. In particular:
- The area under the graph represents the total distance covered by the object
- The slope of the graph represents the acceleration of the object
Answer:
So option (a) is correct option
Explanation:
We have given final speed of the car = 23 m/sec
And initial speed of the car = 30 m/sec
Time in which speed is decreases t = 2 sec
From first equation of motion we know that v = u+at
So acceleration
Negative sign indicate that acceleration will be in opposite direction
So
So option (a) is correct option