Answer:
D)subscript of C in molecular formula = n x subscript of C in empirical formula
Explanation:
THIS IS THE COMPLETE QUESTION BELOW;
.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />
An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is
A compounds CH4, C2H8, C4H12... with empirical formula of CH4. In this case a constant "n" represent the difference that exist between empirical formula and molecular formula, "n" which is a whole number, molecular formula is the numerator.
Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula
The new pressure, P₂ is 6000 atm.
<h3>Calculation:</h3>
Given,
P₁ = 1.5 atm
V₁ = 40 L = 40,000 mL
V₂ = 10 mL
To calculate,
P₂ =?
Boyle's law is applied here.
According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.
PV = constant
Therefore,
P₁V₁ = P₂V₂
Put the above values in the equation,
1.5 × 40,000 = P₂ × 10
P₂ = 1.5 × 4000
P₂ = 6000 atm
Therefore, the new pressure, P₂ is 6000 atm.
Learn more about Boyle's law here:
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Answer:
9 protons
Explanation:
By looking at the periodic table, you will see that Fluorine has 9 protons. Since the number of electrons equal the number of protons, Fluorine has 9 electrons as well. Meanwhile, it's mass number of 19, minus 10 neutrons, gives you 9 protons or electrons. Hence, the atom would be Fluorine.
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Example, when sulfur is burned in the air (one of my favorite chemical reactions) it combines with oxygen in the air to form an oxide. We consider this reaction in the form of a chemical equation: S (sulfur) + O2 (oxygen) |> SO2 (sulfur dioxide)
Answer:
Explanation:Given;
applied force, F = 8000 N
time of force application, t = 15 s
Work done is given as the product of force and displacement. Since the car is unable to move, then the displacement is zero and the work done is zero.
Work done = Force x displacement
Work done = 8000 N x 0
Work done = 0
Therefore, the work done is zero.
