A rubber band is launched horizontally by a student. If the air resistance is negligible, which statement BEST
1 answer:
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Answer:
6.32s
Explanation:
Given parameters:
Length of track and distance covered = 200m
Acceleration = 10m/s²
Unknown:
Time taken to cover the track = ?
Solution:
To solve this problem, we apply one of the motion equations as shown below:
S = ut + at²
S is the distance covered
t is the time taken
a the acceleration
u is the initial velocity
The initial velocity of Superman is 0;
So;
S = at²
200 = x 10 x t²
200 = 5t²
t² = 40
t = 6.32s
I attached a picture of the diagram associated with this question.
Now,
When we check the vertical components of the tension in the rope, we will find that we have two equal components acting upwards.
These two components support the weight and each of them has a value of TcosΘ
The net force acting on the body is zero.
Fnet=Force of tension acting upwards-Force due to weight acting downwards
0 = 2TcosΘ -W
W = 2TcosΘ
T = W / 2cosΘ
Now,
When we check the vertical components of the tension in the rope, we will find that we have two equal components acting upwards.
These two components support the weight and each of them has a value of TcosΘ
The net force acting on the body is zero.
Fnet=Force of tension acting upwards-Force due to weight acting downwards
0 = 2TcosΘ -W
W = 2TcosΘ
T = W / 2cosΘ