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Goryan [66]
2 years ago
8

The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk

with an axle through its center.
(a.) What is the moment of inertia of the pulley?

(b.) What is the magnitude of the net torque on the pulley about its axis

(c.) What is the direction of the net torque on the pulley?

(d.) What is the magnitude of the angular acceleration of the pulley?

(e.) What is direction of the angular acceleration?

Physics
1 answer:
aleksandrvk [35]2 years ago
4 0

Answer:

Explanation:

a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²

b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m

c) CCW

d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²

e) CCW

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6.  Since we are not sure if the person in the question is actively lifting the crate, we have to determine the downwards force of the crate due to gravity and compare it to the normal force.  

F = ma

F = (15.3)(-9.8)

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Since the downwards force of the crate is equivalent to the normal force, it means the person is applying no force in picking up the object.  So to pick up a 150N object from scratch, you would have to exert more force than the weight of the object, so the answer is 294N.


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First determine the weight of the object:

F = ma

F = (30)(-9.8)

F = -294N

The crate in question is not moving, so the magnitudes of the forces in the upwards and downwards direction has to equal to 0.

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10.  First find the force of block B to the right due to its acceleration:

F = ma

F = (24)(0.5)

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The sum of the forces in the leftward and rightward direction for block B must equal 12N.

75 - x = 12

x = 63N

So the force of friction of block A on block B is 63N to the left.


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