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Eduardwww [97]
3 years ago
14

Rachel and Jason were pulling on a remote control from opposite ends. If Rachel was pulling west with a force of 100 N and the n

et force was 40 N west, with how much force and in which direction was Jason pulling?
A.60 N west
B.60 N east
C.140 N west
D.140 N east
Physics
1 answer:
juin [17]3 years ago
8 0

-Jason would be pulling with a force of 60N from east, as east is opposite from west, and if the remote control is 40N, and if Rachel is using a force of 100N - 40N would be 60N east.

-Hope this helps! xo

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1. Give three examples, from the lab, where potential energy was converted to kinetic energy: ​
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Answer:

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Furthermore, the standing wave equation is as follows:

y(x,t) = (A\sin(kx))\sin(\omega t) = A\sin(\frac{\omega}{v}x)\sin(\omega t) = A\sin(\frac{2\pi f}{v}x)\sin(2\pi ft) = A\sin(\frac{2\pi}{\lambda}x)\sin(\frac{2\pi v}{\lambda}t) = (2.45\times 10^{-3})\sin(5.7x)\sin(59.94t)

The bead is placed on x = 0.138 m. The maximum velocity is where the derivative of the velocity function equals to zero.

v_y(x,t) = \frac{dy(x,t)}{dt} = \omega A\sin(kx)\cos(\omega t)\\a_y(x,t) = \frac{dv(x,t)}{dt} = -\omega^2A\sin(kx)\sin(\omega t)

a_y(x,t) = -(59.94)^2(2.45\times 10^{-3})\sin((5.7)(0.138))\sin(59.94t) = 0

For this equation to be equal to zero, sin(59.94t) = 0. So,

59.94t = \pi\\t = \pi/59.94 = 0.0524~s

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3 years ago
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