Question

The inductive reactance of the circuit is exactly twice the resistance: XL=2R. Adjust the phasor that represents the voltage across the inductor (VL) at the instant indicated to the proper length and orientation.

Answer 1

Answer:

∅=$63.43^{0}$

Explanation:

z=impedance

$x_{l}$=2R

R=R

The resultant of the resistances in the circuit is called impedance

$x_{l}$ is inductive reactance of the circuit

R is the resistance of the resistor

z=$\sqrt{xl^{2}+R^2 }$

z=$\sqrt{2R^{2}+R^2 }$

Z=$\sqrt{5R^2}$

Z=R$\sqrt{5}$ohms

tan∅=2R/R

tan∅=2

∅=Tan^-1(2)

∅=$63.43^{0}$

phase angle is ∅=$63.43^{0}$