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3 years ago

14

Sort these elements into pairs that would most likely exhibit similar chemical properties. It doesn't matter which pair goes in

which box, so long as the correct elements are paired. Na, O, Ne, Se, Rb, Kr

1 answer:

nikklg [1K]3 years ago

4 0

<em>Answer:</em>

Na = Rb
Ne = Kr
O = Se

<em>Explanation:</em>

According to modern periodic table, the elements present in same group have same chemical properties , because they same valence shell electrons.

<em>Na and Rb:</em>

As these both elements are present in group one, so these are called Alkali metals. Almost all alkali metal have same chemical properties.

<em>Ne and Kr:</em>

Both these elements are present in group 18, called as noble gases.
They have same chemical properties like both are stable and are inert.

<em>O and Se:</em>

Both elements are present in group 16.
Both have same chemical properties.
Both have same valence shell electrons.

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Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>

3 0

3 years ago

the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th

Rainbow [258]

Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

$P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa$

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3 years ago

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Answer:

They form when plates collide. I hope this helps you!

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2 years ago

Tin (II) fluoride, formerly found in many kinds of toothpaste, is formed in this reaction: Sn (s) + 2HF (g) ——> SnF2 (s) + H2

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1.34 L of HF

Explanation:

We have the following chemical reaction:

Sn (s) + 2 HF (g) → SnF₂ (s) + H₂ (g)

First we calculate the number of moles of SnF₂:

number of moles = mass / molecular weight

number of moles of SnF₂ = 5 / 157 = 0.03 moles

From the chemical reaction we see that 1 mole of SnF₂ are produced from 2 moles of SnF₂. This will mean that 0.03 moles of SnF₂ are produced from 0.06 moles of HF.

Now at standard temperature and pressure (STP) we can use the following formula to calculate the volume of HF:

number of moles = volume / 22.4 (L/mole)

volume of HF = number of moles × 22.4

volume of HF = 0.06 × 22.4 = 1.34 L

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3 years ago

A technician needs 500.0mL of a 0.500 M MgCl2 solution for some lab procedures. The stock bottle is labeled 4.00 M MgCl2. What v

mihalych1998 [28]

Answer:

Explanation:

To solve this problem, we need to obtain the number of moles of the solute we desired to prepare;

Number of moles = molarity x volume

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molarity of solution = 0.5M

Number of moles = 0.5 x 0.5 = 0.25moles

Now to know the volume stock to take;

Volume of stock = $\frac{number of moles }{molarity}$

molarity of stock = 4M

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3 years ago