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Hatshy [7]
3 years ago
14

Sort these elements into pairs that would most likely exhibit similar chemical properties. It doesn't matter which pair goes in

which box, so long as the correct elements are paired. Na, O, Ne, Se, Rb, Kr
Chemistry
1 answer:
nikklg [1K]3 years ago
4 0

<em>Answer:</em>

  •                           Na = Rb
  •                           Ne = Kr
  •                           O = Se

<em>Explanation:</em>

  • According to modern periodic table, the elements present in same group have same chemical properties , because they same valence shell electrons.

<em>Na and Rb:</em>

  • As these both elements are present in group one, so these are called Alkali metals. Almost all alkali metal have same chemical properties.

<em>Ne and Kr:</em>

  • Both these elements are present in group 18, called as noble gases.
  • They have same chemical properties like both are stable and are inert.

<em>O and Se:</em>

  • Both elements are present in group 16.
  • Both have same chemical properties.
  • Both have same valence shell electrons.
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1. What is the colour of FeSO4.7H20 crystals?How does this colour change upon heating? Give balanced
svet-max [94.6K]
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</span>2FeSO4 ---> Fe2O3 + SO2 + SO3<span>

2. a. What are redox reactions?
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b.Why is the reaction between MnO2 and HCl a 
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Because there are atoms that are reduced and are oxidized.

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5 0
3 years ago
PLEASE PLEASE PLEASE ANSWER THIS CORRECTLY ASAP 50 POINTS
tresset_1 [31]

If I remember correctly, it would be B. A very large amount of energy is produced from a tremendous mass.

4 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
PLEASE help!!
Alina [70]

Answer:

<h3>KBr + I- ---------> KI + Br-</h3>

Explanation:

Single Displacement reaction is a chemical Reaction in which one element in the salt is replaced with another element

for example,

A-B + C -------> A-C + B

electropositive replaces only electropositive elements from compound. same is true for electronegative element

in first reaction I being electro negative replaces Br from KBr so this is a single displacement reaction

5 0
3 years ago
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