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marshall27 [118]

3 years ago

10

Photosynthesis is the process by which most living things convert the chemical energy in glucose into more accessible chemical e

nergy in ATP. A. True B. False

1 answer:

kotykmax [81]3 years ago

3 0

The correct answer is A

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Calculate the number of moles in 7g of nitrogen gas

Andru [333]

Answer:

<h3>0.2498mol $N_{2}$ </h3>

Explanation:

7gN2 x $\frac{1 mol}{2(14.01) g}$

=0.2498mol N2

Nitrogen gas has the formula $N_{2}$ so therefore that means you would have to multiply the mass in the molar by 2. To solve for the number of moles you need to cancel out the grams, you do this by using the molar mass of nitrgoen gas. You get the value on in the denominator from the periodic table (atomic mass of element). The grams will cancel out, leaving you with the number of moles when you divide 7/2(14.01).

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3 years ago

______ contributes to the nitrogen cycle by removing nitrogen from the air and converting it into a form that is usable by plant

umka21 [38]

Answer: Bacteria✅

Explanation:

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2 years ago

Determination of the chemical composition of the atmospheres of the planets is carried out most effectively by what type of stud

Iteru [2.4K]

ATMOSPHERIC CHEMISTRY

7 0

3 years ago

Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Part A Calculate ΔG for this reaction at 25 ∘C under the following condit

kati45 [8]

<u>Answer:</u> The $\Delta G$ of the reaction at given temperature is -12.964 kJ/mol.

<u>Explanation:</u>

For the given chemical reaction:

$CH_3OH(g)\rightleftharpoons CO(g)+2H_2(g)$

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{CO})\times (p_{H_2}^2)}{p_{CH_3OH}}$

We are given:

$p_{CO}=0.140atm\\p_{H_2}=0.180atm\\p_{CH_3OH}=0.850atm$

Putting values in above equation, we get:

$K_p=\frac{(0.140)\times (0.180)^2}{0.850}\\\\K_p=5.34\times 10^{-3}$

To calculate the Gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 0 J (at equilibrium)

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = $5.34\times 10^{-3}$

Putting values in above equation, we get:

$\Delta G=0+(8.314J/K.mol\times 298K\times \ln(5.34\times 10^{-3}))\\\\\Delta G=-12963.96J/mol=-12.964kJ/mol$

Hence, the $\Delta G$ of the reaction at given temperature is -12.964 kJ/mol.

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3 years ago

An element or compound which occurs naturally in the earth is a ___?

Rzqust [24]

An element or compound which occurs naturally in the earth is a mineral

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3 years ago

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