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2 years ago

Write the IUPAC names for the following compounds.

Chemistry

1 answer:

atroni [7]2 years ago

5 0

Benzine
Bromine
Clorine

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This drawing shows the internal anatomy of a sponge.

Evgen [1.6K]

Answer:

there is no drawing

Explanation:

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2 years ago

What determines the traits of offspring?A.Food sources that have been genetically engineered B.Literary metaphors and exciting c

iren2701 [21]

Answer:

D. Genes received from the offsprings parents.

Explanation:

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3 years ago

What are the chemical symbols for the two elements found in iron oxide

Gnom [1K]

For Iron: $Fe$

For Oxygen: $O$

These are the two chemical symbols for the two elements found in Iron Oxide.

7 0

3 years ago

Read 2 more answers

How many grams of NH3 can be produced from 12.0g of H2?

RSB [31]

Answer:

Balanced reaction:

3 H2 (g) + N2 (g) → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3. The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

8 0

1 year ago

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

2 years ago