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allochka39001 [22]
3 years ago
13

a scientist divided a population of fruit flies into two containers, each with a different kind of food. then she bred the fruit

flies under these conditions for many generations. lastly, she put the fruit flies from the two containers together again and observed which flies mated. which question was the scientist most likely testing? a. do well-fed fruit flies make good pets? b. what kind of food do fruit flies prefer? c. how many species of fruit flies can mate with each other? d. will fruit flies bred under different conditions mate?
Physics
1 answer:
kati45 [8]3 years ago
4 0
<span>d. will fruit flies bred under different conditions mate? Let's look at the possible choices and see which of them make any sense given the experiment. a. do well-fed fruit flies make good pets? Seems kinda silly, but if this were the question being asked, I suspect the experiment would have some fruit flies that were well fed as well as some fruit flies that were starved and would then compare how those 2 populations of fruit flies interacted with people. But that wasn't done, so it's unlikely this is the question being asked. b. what kind of food do fruit flies prefer? Each population of fruit flies weren't given a choice as to available foods. So their preferences didn't come into play about what they were allowed to eat. So this question is also unlikely. c. how many species of fruit flies can mate with each other? The scientist started with a single population and divided it into two sub groups. There doesn't seem to be a large number of species of different fruit flies here, so this is also an unlikely question. d. will fruit flies bred under different conditions mate? The scientist started with a single population of fruit flies and divided them into two groups. Each group was allowed to breed for many generations with a different food for each group (e.g. Allowed to breed under different conditions). After they were both well established, the groups were merged together and observed which ones mated. It looks like this question is being answered. So this is the correct solution.</span>
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A particle with charge −− 5.90 nCnC is moving in a uniform magnetic field B⃗ =−(B→=−( 1.28 TT )k^k^. The magnetic force on the p
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Answer:

Explanation:

Given that,

Charge q=-5.90nC

Magnetic field B= -1.28T k

And the magnetic force

F =−( 3.70×10−7N )i+( 7.60×10−7N )j

Let the velocity be V(xi + yj + zk)

Then, the force is given as

Note i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

The force in a magnetic field is given as

F= q(v×B)

−( 3.70×10−7N )i+( 7.60×10−7N )j =

q(xi + yj + zk) × -1.28k

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28x i×k - 1.28y j×k - 1.28z k×k)

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( 1.28xj - 1.28y i )

−( 3.70×10−7N )i+( 7.60×10−7N )j=

q( -1.28y i + 1.28x j)

So comparing comparing coefficients

let compare x axis component

-( 3.70×10−7N )i=-1.28qy i

−3.70×10−7N = -1.28qy

y= -3.7×10^-7/-1.28q

y= -3.7×10^-7/-1.28×-5.90×10^-9)

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y≈-49m/s

Let compare y-axisaxis

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7.6×10−7N = 1.28qx

x= 7.6×10^-7/1.28q

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x=-100.64m/s

a. Then, the velocity of the x component is x= -100.64m/s

b. Also, the velocity component of the y axis is y=-49m/s

c. We will compute

V•F

V=-100.64i -49j

F=−( 3.70×10−7 N )i+( 7.60×10−7 N )j

Note

i.j=j.i=0. Also i.i = j.j =1

V•F is

(-100.64i-49j)•−(3.70×10−7N)i+(7.60×10−7 N )j =

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V•F=0

d. Angle between V and F

V•F=|V||F|Cosx

0=|V||F|Cosx

Cosx=0

x= arccos(0)

x=90°

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DanielleElmas [232]

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where

v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s, where f is the frequency

A=0.600 mm=6\cdot 10^{-4} m is the amplitude

Therefore, the maximum speed is

v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s

b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

m=0.0270 g=2.7\cdot 10^{-5} kg is the mass of the fly

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Substituting into the equation, we find

K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J

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The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

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X = Vx(t)

t = X/Vx

t = X/Vcosθ

t = (70.67) / (45 x cos10)

t = 1.6 s

When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.

Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

Learn more about velocity of projectile here: brainly.com/question/12870645

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2 years ago
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Rom4ik [11]

Answer:

An ammeter.

Explanation:

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