When an object is becomes warm its an example of exothermic reaction.
Answer:
Our final answer is option (c) that is :
A resonant mode of your vocal tract.
Explanation:
Lets understand pitch of a sound first:
Pitch: Is the rate of vibrations produced and also the degree of lowness and highness of a tone.
Pitch formant:
When we take air inside our vocal tract it oscillates at different pitches depending upon the cast and capacity of the opening of the vocal tract.
Formant comes from the vocal tract and also at a resonance of our vocal tract.
So basically the vocal tract play a vital role for the formant.
Final answer is : A formant is a resonant mode of our vocal tract.
In contrast to quiet eruptions, other volcanoes erupt explosively. Mount St. Helens, for instance, spewed lava high in the air when it erupted. Two things control the type of eruption: how much water vapor and other gasses are in the magma and whether the magma is basaltic or granitic. Basaltic magma tends to ooze out gently in a thin, quiet eruption, while granitic magma is thicker and becomes trapped inside the volcano's vents. Once the pressure grows enough to force out the magma, it explodes.
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Answer:
D=387.28m
Explanation:
At the moment where the toss is made 
, so we need both equations:
For the red car:
With initial speed of 0 and acceleration of 6.12m/s^2.
For the green car:
With 
and Xo = 200m
Since both positions will be the same:
Solving for t:
t1 = -5.8s and t1 =11.25s
Replacing t = 11.25 on either equation to find the displacement:
Answer:
Explanation:
This problem bothers on the energy stored in a spring in relation to conservation of energy
Given data
Mass of block m =200g
To kg= 200/1000= 0.2kg
Spring constant k = 1.4kN/m
=1400N/m
Compression x= 10cm
In meter x=10/100 = 0.1m
Using energy considerations or energy conservation principles
The potential energy stored in the spring equals the kinetic energy with which the block move away from the spring
Potential Energy stored in spring
P.E=1/2kx^2
Kinetic energy of the block
K.E =1/mv^2
Where v = velocity of the block
K.E=P.E (energy consideration)
1/2kx^2=1/mv^2
Kx^2= mv^2
Solving for v we have
v^2= (kx^2)/m
v^2= (1400*0.1^2)/0.2
v^2= (14)/0.2
v^2= 70
v= √70
v= 8.36m/s
a. Distance moved if the ramp exerts no force on the block
Is
S= v^2/2gsinθ
Assuming g= 9. 81m/s^2
S= (8.36)^2/2*9.81*sin60
S= 69.88/19.62*0.866
S= 69.88/16.99
S= 4.11m
