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alexandr1967 [171]
3 years ago
9

Which of the outer planets is the biggest A.jupiter B.saturn C.your anus D.neptune

Chemistry
2 answers:
Alina [70]3 years ago
5 0
A. Jupiter. is the correct answer. Mark as brainliest please.

masha68 [24]3 years ago
4 0
It’s spelt Uranus by the way. The answer is Jupiter
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3. Students measured the mass of the reactants and products for a combustion reaction they observed.
coldgirl [10]

Answer:

A. Students made a measurement error, because ending with more products is impossible.

Explanation:

The law of conversation of matter tells us that in a chemical reaction, matter is never created or destroyed, it's simply converted from one form to another. So the mass of reactants should always equal the mass of the products in a chemical reaction. If there is excess mass in the product, the students have made an error of some kind.

4 0
3 years ago
a heliox tank contains 32% helium and 68% oxygen. the total pressure in the tank is 395 kPa. What is the partial pressure of oxy
trapecia [35]

Answer:

Pp O2 = 82.944 KPa

Explanation:

heliox tank:

∴ %wt He = 32%

∴ %wt O2 = 68%

∴ Pt = 395 KPa

⇒ Pp O2 = ?

assuming a mix of ideal gases at the temperature and volumen of the mix:

∴ Pi = RTni/V

∴ Pt = RTnt/V

⇒ Pi/Pt = ni/nt = Xi

⇒ Pi = (Xi)*(Pt)

∴ Xi: molar fraction (ni/nt)

⇒ 0.68 = mass O2/mass mix

assuming mass mix = 100 g

⇒ mass O2 = 68 g

∴ molar mass O2 = 32 g/mol

⇒ moles O2 = (68 g)(mol/32 g) = 2.125 mol O2

⇒ mass He = 32 g

∴ molar mass He = 4.0026 g/mol

⇒ moles He = (32 g)(mol/4.0026 g) = 7.995 mol He

⇒ nt = nO2 + nHe = 2.125 mol + 7.995 mol = 10.12 moles

molar fraction O2:

⇒ X O2 = nO2/nt = (2.125 mol/10.12 mol) = 0.2099

⇒ Pp O2 = (X O2)(Pt)

⇒ Pp O2 = (0.2099)(395 KPa)

⇒ Pp O2 = 82.944 KPa

6 0
3 years ago
PLEASE HELP
natima [27]

Answer:

D. Microwave, Blue Visible Light, Ultraviolet, Gamma

Explanation:

colors longest to shortest are

red green blue violet

longest wavelength to shortest:

radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays.

3 0
3 years ago
The half-life of barium-131 is 12.0 days. How many grams of
dimulka [17.4K]

Let's see

\\ \rm\Rrightarrow A=A_o(0.5)^{\frac{t}{H}}

  • H is half-life

\\ \rm\Rrightarrow A=10(0.5)^{\frac{60}{12}}

\\ \rm\Rrightarrow A=10(0.5)^5

\\ \rm\Rrightarrow A=10(0.03125)

\\ \rm\Rrightarrow A=0.3125g

3 0
2 years ago
What is the pH of a 0.30 M solution of Ca(OH)2?
mario62 [17]

Explanation:

30 to the second power

4 0
3 years ago
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