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pantera1 [17]
3 years ago
15

What is the formula for finding the velocity?

Physics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

v = Δs/Δt

and use this calcultor"Velocity Calculator | Definition | Formula - Omni Calculator"if u have problems to slove.cos

Explanation:

blondinia [14]3 years ago
4 0
I hope this answers your question and helps:)

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Which transformation of energy occurs when a fan is turned on and the blades start to rotate?
Ksju [112]

Answer:

kinetic energy

Explanation:

A wind turbine transforms the mechanical energy of wind into electrical energy. A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion. As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator

5 0
3 years ago
When a piece of aluminium foil is taken out of the oven and cools from 1000C to 500C. What is the change in temperature?
zmey [24]

Answer:

Conduction

Explanation:

When one object touches another heat moves through it (think of a saucepan on a hot stove). Aluminium foil is a great conductor of heat, which means it is a poor insulator when it is in direct contact with something hot.

3 0
3 years ago
A 5 kg box drops a distance of 10 m to the ground. If 70% of the initial potential energy goes into increasing the internal ener
Elina [12.6K]

Answer:

Explanation:

From the given information:

The initial PE (PE)_i = m×g×h

= 5 kg × 9.81 m/s² × 10 m

= 490.5 J

The change in Potential energy P.E of the box is:

ΔP.E = P.E_f -P.E_i

ΔP.E = 0 - (PE)_i

ΔP.E = -P.E_i

If we take a look at conservation of total energy for determining the change in the internal energy of the box;

\Delta P.E + \Delta K.E + \Delta U = 0

\Delta U = -\Delta P.E - \Delta K.E

this can be re-written as:

\Delta U =- (-\Delta P.E_i) - \Delta K.E

Here, K.E = 0

Also, 70% goes into raising the internal energy for the box;

Thus,

\Delta U =(70\%) \Delta P.E_i-0

\Delta U =(0.70) (490.5)

ΔU = 343.35  J

Thus, the magnitude of the increase is = 343.35 J

7 0
3 years ago
Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direc
Lerok [7]

Answer:

424.26 m/s

Explanation:

Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q

The relative speed will be calculated by using pythagorean theorem

Relative speed = sqrt(300^2 + 300^2)

Relative speed = sqrt( 180000 )

Relative speed = 424.26 m/s

Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s

7 0
3 years ago
The magnitude of the momentum of an object is the product of its mass m and speed v. If m = 3 kg and v = 1.5 m/s, what is the ma
Oliga [24]

Answer:

Momentum, p = 5 kg-m/s

Explanation:

The magnitude of the momentum of an object is the product of its mass m and speed v i.e.

p = m v

Mass, m = 3 kg

Velocity, v = 1.5 m/s

So, momentum of this object is given by :

p=3\ kg\times 1.5\ m/s

p = 4.5 kg-m/s

or

p = 5 kg-m/s

So, the magnitude of momentum is 5 kg-m/s. Hence, this is the required solution.

5 0
3 years ago
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