The K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion
All of this truly implies is that one of these bonds breaks in a hydrolysis process (a water-mediated breakdown reaction), releasing a sizable amount of energy.
The following reaction results in the hydrolysis of ATP to ADP:
ATP+H2O⇋ADP+Pi+energy
The hydrolysis of ATP to ADP is reversible, like the majority of chemical processes.
Energy is needed for the reverse process, which creates ATP from ADP and Pitext P iPi start subscript, P, end subscript, start subscript, I end subscript.
Because cells frequently use (hydrolyze) ATP molecules and depend on constant production of replacement ATP, ATP regeneration is crucial1^1.
Hence the K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion
Learn more about hydrolysis here:
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Option E, Real gas particles have more complex interactions than ideal gas particles.
In ideal gases, there is absolutely no interaction between any atoms. At all. Atoms simply don't bump into each other in ideal gases.
Obviously, you know that's unrealistic. In real gases, atoms collide into each other all the time.
-T.B.
Carbon-14 and Uranium-238 have something we call a half live, which is basically a known time period for it to change half of its C-14 or U-238 radioactively decay. Since we know how long that is 5730 years for Carbon-14 for half a sample to deteriorate, than we can figure out how old it is.
Answer:
94.325 g
Explanation:
We'll begin by converting 350 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
350 mL = 350 mL × 1 L /1000 mL
350 mL = 0.35 L
Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:
Volume = 0.35 L
Molarity of KC₂H₃O₂ = 2.75 M
Mole of KC₂H₃O₂ =?
Molarity = mole /Volume
2.75 = Mole of KC₂H₃O₂ / 0.35
Cross multiply
Mole of KC₂H₃O₂ = 2.75 × 0.35
Mole of KC₂H₃O₂ = 0.9625 mole
Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:
Mole of KC₂H₃O₂ = 0.9625 mole
Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)
= 39 + 24 + 3 + 32
= 98 g/mol
Mass of KC₂H₃O₂ =?
Mass = mole × molar mass
Mass of KC₂H₃O₂ = 0.9625 × 98
Mass of KC₂H₃O₂ = 94.325 g
Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g
