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bagirrra123 [75]
3 years ago
11

Passengers on an airplane move from rest to 86 meters per second before the airplane takes off. If the airplane takes 100 second

s to take off what is the acceleration, in m/s^2, of the airplane? Show your answer to one decimal point. Make sure you include the proper unit. Do not put a space between the number and the unit!
Physics
1 answer:
VikaD [51]3 years ago
4 0

Utilize the formula:  V _{f} = V _{i} + a\Delta t

V _{f} = Final Velocity (86 m/s)

V _{f} = Initial Velocity (0 m/s)

a = acceleration (m/s²)

\Deltat = Time (100 seconds)

As a result,

86 m/s = 0 + (a)(100 seconds)

Using algebra, divide 86 m/s by 100 seconds:

86 m/s = 100a

a = 0.86 m/s²

Rounded to one decimal place: 0.9 m/s²

Let me know if you have any questions!

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Elza [17]

We can answer this using one of the equations of linear motion:

v = d / t

where:

v = velocity

d = distance

t = time

<span>In the problem, we are asked to find for the time in which Driver B will catch up to Driver A. Therefore,  find the time when dA = dB. Rearranging the equation and equation dA and dB will result in:</span>

<span>vA * tA = vB * tB  ---> 1</span>

It was given that:

vA = 68 mph

tA = tB + 3 (since person A was travelling 3 hours earlier)

vB = 85 mph

tB = unknown

Substituting into equation 1:

68 * (tB + 3) = 85 * tB

68 tB + 204 = 85 tB

tB = 12 hrs

Therefore driver B would catch up to driver A after 12 hrs.

 

 

<span> </span>

5 0
3 years ago
2. A string with a length of 0.9m that is fixed at both ends
aliina [53]

Answer:

2a.) Wavelength = 1.8 m

2b.) F = 66.67 Hz

3a.) Find the attached file

3b.) Wavelength = 0.6 m

Explanation:

Given that the

Length L = 0.9m

Wavelength (λ) = 2L/n

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If n = 1, then

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b.)

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Given that V = 120 m/s

V = Fλ

But λ = 2L, therefore,

F = V/2L

F = 120/1.8

F = 66.67 Hz

3. b.) If there are two node, the position will be in 3rd position which is 3rd harmonic

Using the same formula,

Wavelength (λ) = 2L/n

Where n = 3

Wavelength (λ) = 2 × 0.9/3

Wavelength (λ) = 0.6 m

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kramer

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C

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