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Slav-nsk [51]
3 years ago
10

Sunlight travels 150,000,000 km from the sun to the earth because of?

Physics
1 answer:
padilas [110]3 years ago
8 0
The Speed of Light.
Photons emitted from the surface of the sun to travel across the vacuum of space to reach out eyes
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Will two separate 50db sounds together constitute a 100db sound explain mathematical
vfiekz [6]
Putting together two distinct 50 dB sound, do not create a 100 dB sound. Since decibels are logarithm of energy, creating two sounds together only makes the energy increase but the logarithm only goes up by somehow little. So increasing the sound by 10 dB, only makes it 10000 times louder because each 10 dB increase in sound makes the sound 10 times louder.

Twice as loud is an increase of 10Log (2) = 3.01 dB. So, 53,01 dB is twice as loud as 50dB.
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Ice is placed in hot water. What happens to the temperature of the ice and the water?
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An object starts at 4m/s and accelerates to 6m/s in 10 seconds. Find its displacement.
Natalka [10]

Answer:

Explanation:

The 2 equations we need here are, first:

a=\frac{v_f-v_0}{t} and then once we solve for the acceleration here:

v^2=v_0^2+2aΔx

Solving for acceleration:

a=\frac{6-4}{10}=\frac{1}{5}\frac{m}{s^2} and now we will use that in the other equation:

6^2=4^2+2(\frac{1}{5})Δx and

36 = 16 + \frac{2}{5}Δx and

20 = \frac{2}{5}Δx and

\frac{5}{2}(20)= Δx so

Δx = 50 m

6 0
3 years ago
What is required foe electricity to flow
lukranit [14]
Conductivity is required for the electric current to flow.
5 0
3 years ago
A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex
Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

\text{Efficiency of the heat engine} = \eta = 26\% = 0.26

\text{Energy taken in by the heat engine during each cycle} = Q_h

\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J

\eta = 1 - \frac{Q_{c}}{Q_{h}}

0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}

\frac{8.55* 10^{3}}{Q_{h}} = 0.74

Q_h = \frac{8.55*10^3}{0.74}

Q_h = 11.554*10^3J

PART A)

Work done by the heat engine in each cycle = W

W = Q_h-Q_c

W = 11.554*10^3J-8.55*10^3J

W = 3004J

According to the value given we have that,

P = 4.0kW

P = 4000W

Power is defined as the variation of energy as a function of time therefore,

P = \frac{W}{t}

4000W = \frac{3004J}{t}

t = \frac{3004}{4000}

t = 0.75s

Therefore the interval for each cycle is 0.75s

5 0
3 years ago
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