Answer:
D. Downshift to allow you to turn more sharply
 
        
             
        
        
        
Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
Work done is force x distance 
so Work done = 0.085 x 20g x 28
 = 466.956 J
        
             
        
        
        
Answer:
hope this helps i think the answer is C
 
        
             
        
        
        
Answer:
The final speed of the crate is 12.07 m/s. 
Explanation:
For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:


Now, we can calculate the final speed of the crate at the end of 10.0 m:
 
                   
 
     
For the next 10.5 meters we have frictional force:


So, the acceleration is:
 
 
The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so: 
 
   
 
   
 
Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.  
I hope it helps you!