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3 years ago

How does the number of each type of particle in a sodium ion compare with the number of each type of particle in a sodium atom?

Physics

1 answer:

anyanavicka [17]3 years ago

3 0

<h3>Answer and explanation;</h3>

A neutral sodium atom contains 11 protons, 12 neutrons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1. Thus; Sodium atom is neutral whereas sodium ion is a charged species with a charge of +1.
Sodium ion is positively charged. In sodium ion, there are 11 protons and 12 neutrons but 10 electrons, i.e., sodium ion contains lesser number of electrons. Additionally,the size of sodium ion is smaller than that of sodium atom.

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A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th

Taya2010 [7]

Answer:

The greatest extension of the spring is $\bf{0.055~m}$ and the maximum speed of the block is $\bf{0.695~m/s}$ .

Explanation:

Given:

The mass of the block is, $m = 0.50~kg$

The spring constant of the spring is, $k = 80~N/m$

The mechanical energy of the block is, $E = 0.12~J$

When a particle is oscillating in a simple harmonic way, its total energy is given by

$E = \dfrac{1}{2}m\omega^{2}a^{2}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

where $\omega$ is the angular velocity of the mass and $a$ is the amplitude of its motion.

The relation between angular velocity and spring constant is given by

$\omega = \sqrt{\dfrac{k}{m}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Substituting equation (2) in equation (1), we have

$~~~~~~&& E = \dfrac{1}{2}ka^{2}\\&or,& a = \sqrt{\dfrac{2E}{k}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)$

Substituting $0.12~J$ for $E$ and $80~N/m$ for $k$ in equation (3), we can write

$a &=& \sqrt{\dfrac{2(0.12~J)}{80~N/m}}\\~~~&=& 0.055~m$

The relation between the maximum velocity and the amplitude is given by

$v_{m} &=& \omega a\\~~~~&=& \sqrt{\dfrac{k}{m}}a~~~~~~~~~~~~~~~~~~~~~~~~~~~~(4)$

Substituting $80~N/m$ for $k$ , $0.50~kg$ for $m$ and $0.055~m$ for $a$ in equation (4), we have

$v_{m} &=& \sqrt{\dfrac{80~N/m}{0.50~kg}}(0.055~m)\\~~~&=& 0.695~m/s$

8 0

4 years ago

answer A vertical spring stretches 3.4 cm when a 8-g object is hung from it. The object is replaced with a block of mass 26 g th

victus00 [196]

Answer:

0.695s

Explanation:

From Hooke's law, the restoring force is given has

F = -ky .......1

Where F is the force, y is the spring displacement and k force constant of the spring.

Also recall,

F=mg ............ 2

Where m is the mass of object, g is the acceleration due to gravity.

Equating 1 and 2

Ky = mg

Given that g=9.8m/s2 , y is 3.4cm and g is 8g

K×3.4/100m =8/1000kg × 9.8m/s2

K= ( 0.008kg × 9.8m/s2 ) ÷ 0.034

K= 0.0784÷0.035

K=2.24N/m

Mass ofvthe second object is 25g =0.025kg

Period of oscillation T

T=2π√m/k

T=2×3.142√0.025/2.24

T=6.284√0.0111

T=0.659seconds

8 0

3 years ago

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Fuel cells have been developed that can generate a large amount of energy. For example, a hydrogen fuel cell works by combining

maksim [4K]

Electric power is given by:
Power = voltage x current
10000 = 15.8V
V = 633 Volts

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4 years ago

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Hoochie [10]

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3 years ago

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miss Akunina [59]

Answer:

Vagetagble, fruits,fresh milk and juice vitamins c

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