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julia-pushkina [17]
3 years ago
12

How does the number of each type of particle in a sodium ion compare with the number of each type of particle in a sodium atom?

Physics
1 answer:
anyanavicka [17]3 years ago
3 0
<h3><u>Answer and explanation;</u></h3>
  • <u><em>A neutral sodium atom contains 11 protons, 12 neutrons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1.</em></u> Thus; Sodium atom is neutral whereas sodium ion is a charged species with a charge of +1.
  • <u><em>Sodium ion is positively charged. In sodium ion, there are 11 protons and 12 neutrons but 10 electrons</em></u>, i.e., sodium ion contains lesser number of electrons. Additionally,the size of sodium ion is smaller than that of sodium atom.

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a_t = 1.1ft/s^2

PART A )

a_c = \frac{V^2}{R}

a_c = \frac{V^2}{350}

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 5.25ft/s^2

a = \sqrt{a_t^2+a_r^2}

5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

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Now calculate the angular velocity of the motorcycle

v = r\omega

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Calculate the angular acceleration of the motorcycle

a_t = r\alpha

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Calculate the time needed by the motorcycle to reach an acceleration of

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PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is 6.75ft/s^2

a = \sqrt{a_t^2+a_r^2}

6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

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PART C)

Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is 21.5ft/s

a_r = \frac{v^2}{R}

a_r = \frac{21.5^2}{350}

a_r =1.3207ft/s^2

Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is 21.5ft/s

a = \sqrt{a_t^2+a_r^2}

a = \sqrt{(1.1)^2+(1.3207)^2}

a = 1.7187ft/s^2

PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is 6.75ft/s^2

a = \sqrt{a_t^2+a_r^2}

6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}

45.5625 = 1.21 + \frac{v^4}{122500}

v=48.2796ft/s

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