A 51-g rubber ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact w
1 answer:
You might be interested in
Answer:
= -32.53 m / s
this velocity is directed downwards
Explanation:
This is a free fall exercise, let's use the expression
= v_{oy}^{2} + 2 g (y -yo)
where we are assuming that there is friction with the air, as the body falls its initial velocity is zero
v_{oy} = √ 2g (y - y₀)
let's calculate
v_{y} = √ (2 9.8 (0-54.0))
= -32.53 m / s
this velocity is directed downwards
Answer:
45.6m
Explanation:
The equation for the position y of an object in free fall is:
With the given values in the question the equation has one unknown v₀:
Solving for t=1:
1)
To find the hight of the tower you can use the concept of energy conservation:
The energy of the body 1 sec before it hits the ground:
2)
If h is the height of the tower, the energy on top of the tower:
3)
Combining equation 2 and 3 and solving for h:
4)
Combining equation 1 and 4: