A 51-g rubber ball is released from rest and falls vertically onto a steel plate. The ball strikes the plate and is in contact w
1 answer:
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Answer:
Explanation:
We are given that
Mass,
Radius,r=0.8 m
Height,h=2.9 m
We have to find the angular acceleration of the cylinder.
According to question
Where
Substitute the value
Where
Angular acceleration,
Answer:
0.231 N
Explanation:
To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be
If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:
According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is
So the force acting on the other end to generate this torque mush be: