Answer:
Incomplete question: "Each block has a mass of 0.2 kg"
The speed of the two-block system's center of mass just before the blocks collide is 2.9489 m/s
Explanation:
Given data:
θ = angle of the surface = 37°
m = mass of each block = 0.2 kg
v = speed = 0.35 m/s
t = time to collision = 0.5 s
Question: What is the speed of the two-block system's center of mass just before the blocks collide, vf = ?
Change in momentum:
![delta(P)=F*delta(t)](https://tex.z-dn.net/?f=delta%28P%29%3DF%2Adelta%28t%29)
![P_{f} -P_{i}=F*delta(t)](https://tex.z-dn.net/?f=P_%7Bf%7D%20-P_%7Bi%7D%3DF%2Adelta%28t%29)
![2m(v_{f} -v_{i})=F*delta(t)](https://tex.z-dn.net/?f=2m%28v_%7Bf%7D%20-v_%7Bi%7D%29%3DF%2Adelta%28t%29)
![v_{i} =0.35-0.35=0](https://tex.z-dn.net/?f=v_%7Bi%7D%20%3D0.35-0.35%3D0)
It is neccesary calculate the force:
![F=(m+m)*g*sin\theta](https://tex.z-dn.net/?f=F%3D%28m%2Bm%29%2Ag%2Asin%5Ctheta)
Here, g = gravity = 9.8 m/s²
![F=(0.2+0.2)*9.8*sin37=2.3591N](https://tex.z-dn.net/?f=F%3D%280.2%2B0.2%29%2A9.8%2Asin37%3D2.3591N)
![v_{f} =\frac{F*delta(t)}{2m} =\frac{2.3591*0.5}{2*0.2} =2.9489m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3D%5Cfrac%7BF%2Adelta%28t%29%7D%7B2m%7D%20%3D%5Cfrac%7B2.3591%2A0.5%7D%7B2%2A0.2%7D%20%3D2.9489m%2Fs)
Answer:
what are the answer choices
Explanation:
i dont know the choices so i say count the stuff they recycle, and add the score to the days before.
Answer:
The penny would take 10 seconds to fall.
Explanation:
Hope this helps!!