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svet-max [94.6K]
3 years ago
15

I need help so bad does anyone know this ​

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer: line C is the correct answer. please mark brainliest

Step-by-step explanation:

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Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

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