1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rodikova [14]
3 years ago
8

Which of the following equations is balanced for charge and mass?

Chemistry
2 answers:
Nataliya [291]3 years ago
8 0
<span>B. S⁰(s) + 2H⁺ + 2e⁻ –--> H2S⁰(g)

by mass: 1 S  and 2 H ----> 2 H and 1S  True.
by charge : 0 +(2*(+1)) + 2*(-1) = 0, 0+2-2=0, 0 = 0  True.</span>
mamaluj [8]3 years ago
4 0

 

The following equation(option B) is balanced for charge and mass

A. S(s) + 2H+ → H2S(g) + 2e–


B. S(s) + 2H+  + 2e–  →  H2S(g)


C. S(s) + 2e- →H2S(g)


D. S(s) + 2H+→ H2S(g)


S(s) + 2H+  + 2e–  →  H2S(g)



here S is one on either sides

H is two on either sides, hence mass is balanced.


And charge is also balanced,


as  2H+ has +2 charge

and 2e- has -2 charge,thus

total charge on left side is +2-2 = 0

and charge on right side is also zero here or no charge on either sides.

You might be interested in
How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s2? a 1003 N b 0.003 N c 3000 N d 333.3 N
Bogdan [553]

Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

Mass → 1000 kg

a → 3 m/s²

F = 1000 kg . 3m/s² →  3000 N

1 N = 1 kg .  m/s²  according to SI, Internation System of units.

7 0
2 years ago
What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough
olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0
2 years ago
What is the mass of a liquid having a density of 1.40 g/mL and a volume of 3.090 L
riadik2000 [5.3K]
It has a mass of 4.326 grams. 


4 0
2 years ago
Read 2 more answers
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}

P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}

P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times  35.0} = 0.776969038566

∴ The final pressure P₂ ≈ 0.78 atm.

4 0
3 years ago
How much energy (in Joules) is needed to increase the temperature of 25 grams of glass by 5.0C. Aluminum Iron Glass Copper Water
vitfil [10]

Answer:

25 grams of glass by 5.oc aluminium iron glass copper water

4 0
2 years ago
Other questions:
  • Ben is pushing a small trolley 10 N to the north and but Gary is pushing the trolley 5 N to the south. What is the total applied
    14·1 answer
  • Is colour a chemical or physical
    12·1 answer
  • When a colorless aqueous solution of lead nitrate is combined with a colorless aqueous solution of sodium iodide a bright yellow
    5·1 answer
  • The world produces about 3.9 billion tons of food every year. Of that amount, approximately 2.6 billion tons is consumed each ye
    11·2 answers
  • If 1.00 calorie = 4.18kj, how many kj of energy can be released by an apple containing 125 cal?
    6·1 answer
  • How do plants store glucose?
    7·1 answer
  • Reactant A contains 40 J of energy, and Reactant B contains 33.5 J of energy. The reactants combine to form product AB, which co
    11·1 answer
  • C6H12O6 + 6O2 --&gt; 6H2O + 6H2O
    8·1 answer
  • In science, all ideas are not tested with evidence from the natural world.
    5·2 answers
  • Convert the following word equation into a formula equation
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!